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What is the oxidation number for HCI?
the oxidation number of the molecule HCl is 0.because H has Oxidation no +1 and Cl has -1 oxidation no in the HCl.
What is the oxidation number for hydrochloric acid?
In hydrochloric acid (HCl), the oxidation number of hydrogen is +1 and the oxidation number of chlorine is -1.
What is the correct oxidation number for HCI?
The correct oxidation number for HCl is -1 for Cl and +1 for H.
What is the oxidation state of chlorine in HCl?
The oxidation state of chlorine in HCl is -1. In HCl, hydrogen is assigned an oxidation state of +1 because it usually has a +1 charge when bonded to nonmetals. Since the overall charge of HCl is 0, the chlorine must have an oxidation state of -1 to balance the charge.
What is the oxidation number for hydrogen in the compound HC1?
The oxidation number for hydrogen in the compound HCl is +1. Hydrogen typically has an oxidation number of +1 when bonded to nonmetals like chlorine in covalent compounds.
What is the oxidation number for HCI?
the oxidation number of the molecule HCl is 0.because H has Oxidation no +1 and Cl has -1 oxidation no in the HCl.
What is the oxidation number for hydrochloric acid?
In hydrochloric acid (HCl), the oxidation number of hydrogen is +1 and the oxidation number of chlorine is -1.
What is the correct oxidation number for HCI?
The correct oxidation number for HCl is -1 for Cl and +1 for H.
What is the oxidation state of chlorine in HCl?
The oxidation state of chlorine in HCl is -1. In HCl, hydrogen is assigned an oxidation state of +1 because it usually has a +1 charge when bonded to nonmetals. Since the overall charge of HCl is 0, the chlorine must have an oxidation state of -1 to balance the charge.
What is the oxidation number for hydrogen in the compound HC1?
The oxidation number for hydrogen in the compound HCl is +1. Hydrogen typically has an oxidation number of +1 when bonded to nonmetals like chlorine in covalent compounds.
What is the oxidation number of hydrogen in HCl?
O.S. of H = +1 O.S. of O = -2 O.S. of Cl = +1 O.N. of cpd = 0
What is an oxidation number example?
An example of an oxidation number is in the molecule HCl, where hydrogen has an oxidation number of +1 and chlorine has an oxidation number of -1. The sum of the oxidation numbers in a neutral compound is always zero.
What is the most common oxidation number of the element chlorine?
Chlorine is in group 17. It easily accepts an electron from another element to fill its valence shell. As it takes one electron, its oxidation number changes to -1.
How do you tell the charge or oxidation number of an element?
It is calculated by the relative electronegativity. Let's take HCl as an example. Chlorine is the more electronegative element, which partially attracts the electron shared by hydrogen. Hydrogen has partially donated an electron. Therefore in HCl, hydrogen and chlorine have +1 and -1 oxidation numbers respectively.
What is the oxidation number of HClO?
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
Find the charge oxidation number of chromium in CrCl3?
In this case you have a Salt that comes from a binarius acid (HCl) you have to remember in salts you are always using the oxidation number with H (Cl= -1) so Cr is using 3 :) as you have seen im not a English native speaker... sorry for mistakes :D
What is chlorine oxidation number?
It depends on the compound its in. (the range for its oxidation number ranges from -1 to +7 [odd numbers in between are its oxidation numbers exp: -1, +1, +3, +5, +7]) For example if its cl- (only a chlorine ion) then its oxidation number is -1 (simmilar to its valency). If its in the compound NaCl, We know that its total oxidation is 0. (all compunds have an oxidation number of zero) Na has an oxidation number +1. Therefore +1 + x = 0 -> through this you can find the oxidation number of chlorine in this compund. (x representing the oxidation number of chlorine). In this case the answer is x=-1. In the compound HClO4 (perchloric acid), the oxidation number of the total compund is equal to 0. Oxygen has an oxidation number of -2, and hydrogen has an oxidation number of +1. Therefore, (+1) + x + (-2*4) = 0 (oxygen in this compund has 4 atoms so -2 multiplied by 4) Thus: +1 + x + (-8) = 0 +1 + x = 8 x= 8 -1 x= +7 So we can see here that the oxidation number of chlorine has become +7. Do the same for any compound that chlorine is involed in. Hope it helps.
