I assume you mean the oxidation number of Mn in the permanganate ion , MnO4-
The sum of the oxidation numbers is the charge on a polyatomic ion so Mn has an oxidation number of +7 as each O is assigned -2.
The oxidation number of manganese in MnO2 is 4+.
Manganese oxidation number is +4 in MnO2
+6
Oxidation number of MN is +4. Oxidation number of Oxygen is -2
-6 is the oxidation number
The oxidation number of Mn in manganese VII oxide is +7.
K has an oxidation number of +1 O has an oxidation number of (-2) x 4 So... the oxidation number for Mn is whatever is needed to make 1-8 equal to zero. Therefore, the oxidation number for Mn is +7
K has an oxidation number of +1 O has an oxidation number of (-2) x 4 So... the oxidation number for Mn is whatever is needed to make 1-8 equal to zero. Therefore, the oxidation number for Mn is +7
Oxidation number of MN is +4. Oxidation number of Oxygen is -2
-6 is the oxidation number
The oxidation number of Mn in manganese VII oxide is +7.
K has an oxidation number of +1 O has an oxidation number of (-2) x 4 So... the oxidation number for Mn is whatever is needed to make 1-8 equal to zero. Therefore, the oxidation number for Mn is +7
MnO2: oxidation number +4KMnO4: oxidation number +7
K has an oxidation number of +1 O has an oxidation number of (-2) x 4 So... the oxidation number for Mn is whatever is needed to make 1-8 equal to zero. Therefore, the oxidation number for Mn is +7
The oxidation number of Mn in the molecule Mn2 would be 0.
MnO2 manganese(IV) oxide. Oxygen has a -2 oxidation state (oxidation state is a better term here as oxidation number is better used for complexes- they give the same answer for this compound)
Ag2MnO4
First O has an oxidation number of -2; K will an oxidation number of +1 as it is an alkali metal. Therfore the Mn is +6. note that while the manganate ion exists, the question may relate to the permanganate ion MnO4-, so KMnO4, where Mn has oxidation number of +7
O.S. of Mn in Mn(CO)2 is 0.
Lets say the oxidation number of Mn is x oxygen's oxidation number is -2 and the charge on the molecule is 1- so: 1(x) + 4(-2) = 0 x - 8 = 0 x = +8 and then you must remember that there is a negative charge to the molecule. Subtract 1. therefore oxidation number on Mn is +7