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What is th oxidation number for N in NO2?
The oxidation number of N in NO2 is +4. This is because oxygen has an oxidation number of -2, and there are two oxygen atoms in NO2, which gives a total charge of -4. Therefore, the nitrogen atom must have an oxidation number of +4 to balance the charges and make the overall compound neutral.
What are the oxidation numbers of nitrogen in NH4, NO2, and NaNO3?
The oxidation number of nitrogen in NH4 is -3, in NO2 is 3, and in NaNO3 is 5.
What is the oxidation number of nitrogen in NO 2?
The oxidation number of nitrogen in NO2 is +4. Each oxygen atom has an oxidation number of -2, and since the overall charge of NO2 is 0, the nitrogen atom must have an oxidation number of +4 to balance the charges.
What are the oxidation numbers in compound no2?
In the compound NO2, nitrogen has an oxidation number of +4 and each oxygen atom has an oxidation number of -2.
What is the oxidation number of N in N02?
The oxidation number of N in NO2 is +4. Each oxygen atom has an oxidation number of -2, so the sum of the oxidation numbers in NO2 must equal the overall charge of the molecule, which is 0. This means that the oxidation number of N must be +4 to balance the -4 oxidation contributed by the two oxygen atoms.
What is th oxidation number for N in NO2?
The oxidation number of N in NO2 is +4. This is because oxygen has an oxidation number of -2, and there are two oxygen atoms in NO2, which gives a total charge of -4. Therefore, the nitrogen atom must have an oxidation number of +4 to balance the charges and make the overall compound neutral.
What are the oxidation numbers of nitrogen in NH4, NO2, and NaNO3?
The oxidation number of nitrogen in NH4 is -3, in NO2 is 3, and in NaNO3 is 5.
What is the oxidation number of nitrogen in NO 2?
The oxidation number of nitrogen in NO2 is +4. Each oxygen atom has an oxidation number of -2, and since the overall charge of NO2 is 0, the nitrogen atom must have an oxidation number of +4 to balance the charges.
What are the oxidation numbers in compound no2?
In the compound NO2, nitrogen has an oxidation number of +4 and each oxygen atom has an oxidation number of -2.
What is the oxidation number of N in N02?
The oxidation number of N in NO2 is +4. Each oxygen atom has an oxidation number of -2, so the sum of the oxidation numbers in NO2 must equal the overall charge of the molecule, which is 0. This means that the oxidation number of N must be +4 to balance the -4 oxidation contributed by the two oxygen atoms.
What is the oxidation number for NO2?
N is +3, O is -2. The anion has an oxidation number of -1 (equal to its charge)
What is the oxidation number of NO2?
The oxidation number of the ion is -1. Oxygen atoms have -2 oxidation number each. Nitrogen's oxidation number is +3: 4 covalent bonds with oxygen yields +4 and the central negative charge yields -1.
What is the oxidation number of nitrogen in NO2?
The oxidation number of nitrogen in NO2 is +4. This is because oxygen is typically assigned an oxidation number of -2, and since there are two oxygen atoms in NO2, the total oxidation state would be -4. Therefore, nitrogen must have an oxidation number of +4 to balance this out.
What is the oxidation number in NO2?
The oxidation number in NO2 is +4 for nitrogen and -2 for oxygen. In this molecule, nitrogen is assigned an oxidation number of +4 because it is more electronegative than oxygen, which is typically assigned an oxidation number of -2 in compounds.
What is the oxidation number of N in NO2?
The oxidation number of N in NO2 is +4. Each oxygen atom in NO2 has an oxidation state of -2, so the oxidation state of nitrogen can be calculated as follows: 2*(-2) + x = 0, where x is the oxidation state of N. Solving for x gives us x = +4.
What is the oxidation number of nitrito?
The oxidation number of the nitrite ion (NO2-) is -1. The oxidation number of nitrogen in the nitrite ion is +3, and each oxygen atom has an oxidation number of -2.
What is the oxidation number of nitrogen in nitrogen dioxide?
The oxidation number of nitrogen in nitrogen dioxide (NO2) is +4. Each oxygen atom in NO2 has an oxidation number of -2, and since the molecule is neutral, the sum of the oxidation numbers must equal zero. Therefore, the oxidation number of nitrogen is calculated as follows: 2(-2) + x = 0, where x represents the oxidation number of nitrogen. Solving for x gives x = +4.
