+5
The oxidation number for the dihydrogen phosphate ion (H2PO4-) is +1 for each hydrogen atom, -2 for the oxygen atom, and +5 for the phosphorus atom.
NO!!! Phosphates it is '+5' Phosphides it is '-3'
In disodium phosphate (Na2HPO4), each sodium (Na) atom has an oxidation number of +1 since it is in Group 1 of the periodic table. The hydrogen atom (H) has an oxidation number of +1, and the phosphate ion (PO4) as a whole has a charge of -3, making the phosphorus atom (P) have an oxidation number of +5.
To find the oxidation number of phosphorus in phosphate (PO4), consider that oxygen typically has an oxidation number of -2. Since there are four oxygen atoms in phosphate, their total charge is -8. The overall charge of the phosphate ion is -3, so the oxidation number of phosphorus can be calculated as +5 to balance the charges.
The oxidation number of phosphorus (P) in PH3 is -3. This is because hydrogen (H) has an oxidation number of +1, and there are three hydrogen atoms bonded to phosphorus, resulting in a total charge of +3 that is balanced by phosphorus having an oxidation number of -3.
The oxidation number for the dihydrogen phosphate ion (H2PO4-) is +1 for each hydrogen atom, -2 for the oxygen atom, and +5 for the phosphorus atom.
NO!!! Phosphates it is '+5' Phosphides it is '-3'
In disodium phosphate (Na2HPO4), each sodium (Na) atom has an oxidation number of +1 since it is in Group 1 of the periodic table. The hydrogen atom (H) has an oxidation number of +1, and the phosphate ion (PO4) as a whole has a charge of -3, making the phosphorus atom (P) have an oxidation number of +5.
To find the oxidation number of phosphorus in phosphate (PO4), consider that oxygen typically has an oxidation number of -2. Since there are four oxygen atoms in phosphate, their total charge is -8. The overall charge of the phosphate ion is -3, so the oxidation number of phosphorus can be calculated as +5 to balance the charges.
The oxidation number of phosphorus (P) in PH3 is -3. This is because hydrogen (H) has an oxidation number of +1, and there are three hydrogen atoms bonded to phosphorus, resulting in a total charge of +3 that is balanced by phosphorus having an oxidation number of -3.
The oxidation number of phosphorus in chromium(III) phosphate is +5. In chromium(III) phosphate, each chromium ion has a +3 oxidation state, and the overall compound is electrically neutral, so the oxidation number of phosphorus must be +5 to balance the charges.
The oxidation number of phosphorus in PL3 is -3. Each hydrogen has an oxidation number of +1, so in order for the overall charge of the compound to be neutral, phosphorus must have an oxidation number of -3.
The oxidation number of Phosphorus (P) in H3P2O7 is +5. This can be determined by assigning hydrogen an oxidation number of +1 and oxygen an oxidation number of -2, then setting up an equation to solve for the unknown oxidation number of Phosphorus.
P = +5 PO4^3- = -3 4(-2) + p = -3 P =5
+5 The phosphate anion is PO4^(3-) . Using oxygen as the yardstick (standard ) at '-2' The the four oxygens have an overall oxidation of 4 x -2 = -8 Then creating a sum P - 8 = -3 ( The anionic chagre0. P = -3 + 8 P = +5 . NB In the nitrogen group , which includes phosphorus, the elements have variable oxidation states.
The oxidation number of phosphorus in white phosphorus is 0.
The oxidation number of phosphorus in H4P2O7 is +5. This can be calculated by taking into account the known oxidation states of hydrogen (+1) and oxygen (-2), and solving for the unknown oxidation state of phosphorus to ensure the overall charge of the compound is neutral.