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In H2SiOF6, the oxidation number of hydrogen is +1 and the oxidation number of oxygen is -2. Since the overall charge of the compound is 0, the sum of the oxidation numbers must equal 0. Therefore, the oxidation number of silicon (Si) can be calculated as follows:

2(+1) + x + (-2) + 6(-1) = 0 2 + x - 2 - 6 = 0 x - 6 = 0 x = +6

Therefore, the oxidation number of silicon (Si) in H2SiOF6 is +6.

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