What is the oxidation number of bromine in br2?

Answer 1

In the formula NaBrO3, Oxygen will always have a -2 oxidation number. In this case the total number for oxygen in -6 because there are three oxygen atoms. Sodium will always have a +1 oxidation number therefore its total oxidation number is +1. The entire charge has to equal zero so taking what we have now: -6 and +1 we have a -5 left over. Therefore, Bromine must have a +5 oxidation number.

Answer 2

Bromine has an oxidation number of -1. Since it is in group 17, it has seven valence electrons. It wants to have eight, so it will gain an electron. Electrons are negative, that's why the oxidation number is negative.

Answer 3

Since Oxygen is not a peroxide, each Oxygen molecule has an oxidation number of 2-. And since there are 3 molecules: 3*(2-)=6-. Therefore, Br will have a charge of 6+ in order to have the entire compound's charge equal 0.

*Side Note* The polyatomic ion Bromate is BrO3-, in this case, Bromine will be 5+ because the overall charge is supposed to equal 1- because of the negative charge written after the O. (I added this incase you forgot the - symbol after O.)

Answer 4

A bromate ion has the formula BrO3-1. Oxygen in oxyanions is assigned an oxidation number of -2 per atom. The total negative charge in the three oxygen atoms of a bromate ion is therefore -6. Bromine must have an oxidation number of +5 to give a net value of -1 for the entire ion.

Answer 5

The oxidation number of bromine in Br2 is 0 because it is a diatomic molecule, and each bromine atom shares the electrons equally.

Answer 6

Bromine gas (or bromine in any other state of matter except plasma) is a chemical element, and the oxidation number of any element in its elemental state is zero by definition.

Answer 7

Br2 is in pure form.So its Oxidation number is zero.

Answer 8

H is +1 therefor Br is -1.

Answer 9

2

Answer 10

0