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MoS2.
-2 for each S, +4 for Mo
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What is the oxidation number of molybdenum disulphide?
In molybdenum disulfide (MoS2), molybdenum typically has an oxidation state of +4, and sulfur has an oxidation state of -2. Each Mo atom contributes a +4 oxidation state, while each S atom contributes a -2 oxidation state, which balances the overall charge of the compound.
What is the oxidation number of Mo in MoO4 -2?
The oxidation number of oxygen is typically -2, so for the whole MoO4^2- ion (which has a charge of -2), the total oxidation number must sum up to -2. This means that the oxidation number of molybdenum (Mo) in MoO4^2- would be +6.
What is the oxidation number Mo in MoO4-2?
The oxidation number of oxygen is typically -2. Since there are four oxygen atoms in MoO4-2 and the overall charge is -2, the oxidation number of molybdenum (Mo) is calculated to be +6 to balance the negative charge.
What is the oxidation number of Mo in MoO4?
The oxidation number of molybdenum (Mo) in MoO4^2- is +6. This is because the overall charge of the compound is -2, and each oxygen atom has an oxidation number of -2. By setting up an equation (x + 4(-2) = -2), we find that x = +6.
What is the oxidation number of MoO4?
The oxidation number of molybdenum (Mo) in the MoO4^2- ion is +6. This is because oxygen typically has an oxidation number of -2, and there are four oxygen atoms in the persulfate ion (O4^2-), making the total charge -8. For the overall ion to have a charge of -2, molybdenum must have an oxidation number of +6 to balance the charges.
What is the oxidation number of molybdenum disulphide?
In molybdenum disulfide (MoS2), molybdenum typically has an oxidation state of +4, and sulfur has an oxidation state of -2. Each Mo atom contributes a +4 oxidation state, while each S atom contributes a -2 oxidation state, which balances the overall charge of the compound.
What is the oxidation number of Mo in MoO4 -2?
The oxidation number of oxygen is typically -2, so for the whole MoO4^2- ion (which has a charge of -2), the total oxidation number must sum up to -2. This means that the oxidation number of molybdenum (Mo) in MoO4^2- would be +6.
What is the oxidation number Mo in MoO4-2?
The oxidation number of oxygen is typically -2. Since there are four oxygen atoms in MoO4-2 and the overall charge is -2, the oxidation number of molybdenum (Mo) is calculated to be +6 to balance the negative charge.
What is the oxidation number of Mo in MoO4?
The oxidation number of molybdenum (Mo) in MoO4^2- is +6. This is because the overall charge of the compound is -2, and each oxygen atom has an oxidation number of -2. By setting up an equation (x + 4(-2) = -2), we find that x = +6.
What is the oxidation number of MoO4?
The oxidation number of molybdenum (Mo) in the MoO4^2- ion is +6. This is because oxygen typically has an oxidation number of -2, and there are four oxygen atoms in the persulfate ion (O4^2-), making the total charge -8. For the overall ion to have a charge of -2, molybdenum must have an oxidation number of +6 to balance the charges.
What is the oxidation number of Mo in MO4?
If you mean MoO4 the oxidation number of Mo is 8 and the compound would be called Mo(VIII) oxide. This compound does not exist, it is theoretical- teachers and examiners often use such nonexistent compounds as teaching aids- why I don't know- i think it is misleading as there are plenty of real compounds about.
What is the oxidation number of NaMoO3?
In NaMoO3, sodium (Na) has an oxidation number of +1, oxygen (O) has an oxidation number of -2, and the overall charge of the compound is 0. Since there is only one Mo atom in the compound, the oxidation number of molybdenum (Mo) can be calculated to be +6 using the formula: (+1) + x + 3(-2) = 0 where x is the oxidation number of Mo.
What is the formula for a compound of molybdenum phosphorous and oxygen?
MoPO4 is the formula for Molybdenum Phosphate with the Mo in oxidation state III. Mo can have multiple oxidation states. H3PMo12O40 is phosphomolybdic acid - see more information on this species at the related link.
What is the oxidation of (NH4)2MoO4?
In ammonium molybdate, ((NH_4)_2MoO_4), the oxidation states can be determined as follows: the ammonium ion ((NH_4^+)) has a +1 oxidation state, and there are two such ions, contributing +2 overall. The oxide ions ((O^{2-})) each have a -2 oxidation state, contributing -8 overall from the four oxygen atoms. To balance these, molybdenum (Mo) must have an oxidation state of +6, resulting in the overall compound being neutral. Thus, the oxidation state of molybdenum in ((NH_4)_2MoO_4) is +6.
What is the mass number of molybdenum?
The atomic number of molybdenum (Mo) is 42. See the Web Links to the left of this answer for a periodic table with more information about this element!
How much neutrons does molybdenum have?
Most molybdenum atoms have 54 neutrons. The atomic number (number of protons) of molybdenum is 42, and its weight (number of protons and neutrons) is around 96. 96 - 42 = 54.
What is the correct name for Mo2O5?
The correct name for Mo2O5 is molybdenum(V) oxide. In this compound, molybdenum has an oxidation state of +5, which is indicated by the Roman numeral in the name. This oxide is typically used in various chemical applications, including as a catalyst and in the production of other molybdenum compounds.
