Oxidation number of P in H3PO3 is +3. To calculate the oxidation number
H= 1 except when bonded to metal
O is -2 except when bonded to F
The sum of all of the oxidation number on a molecule /ion is equal to the charge so as H3PO3 is a neutral molecule:-
0 = OxP + 3OxH + 3OxO = Oxp + 3 + (-6)
Oxp = +3
H3PO3 is phosphorus acid. However when you try to make it in aqueous solution, it "tautomerises" , turning into phosphonic acid, HPO(OH)2- same formula H3PO3, but its got a P-H bond and a P=O bond. The oxidation number of P is still 3
Phosphorus ahs an ocxidation number of 3. Phosphoric acid, H3PO3 has structure where there is one hydrogen (-H), two hydroxyl groups (-OH) and one oxgen (=O) attached to the central phosphorus P
Using the normal rules, H= +1, O = -2, OH = -1 and balancing out the "charges" we get P =+3
HPO3 = -2
H= +1
O= -2
Ox3=-6
H+P+O3= -2
1+x+-6=-2
-5+x=-2
X=+3
P=+3
+1 for each H; -2 for each O; +5 for each P
+1 for each H, +3 for P, -2 for each O
p=+5
1
zero oxidation number
+1 for each H, +3 for P and -2 for each O
Formula: H3PO3
not sure but 1
1
zero oxidation number
+1 for H +5 for P -2 for O
Phosphorus acid
+1 for each H, +3 for P and -2 for each O
Formula: H3PO3
not sure but 1
31
Element Phosphorus has an oxidation state of -4. No element has oxidation state of +4. Phosphorus is denoted by "P".
The oxidation numbers in PO43- , phosphorus oxidation number=+5; oxygen = -2
+5 for P
The oxidation number of what in K3PO4? In that compound the oxidation number of oxygen is -2, the oxidation number of potassium is +1, and the oxidation number of phosphorus is +5.Realistically, in most compounds you can generally take it as a given that the oxidation number of oxygen is -2 and the oxidation number of any alkali metal is +1. In potassium phosphate, that only leaves the oxidation number of phosphorus to figure out, and since they have to come out to a total of zero ...The oxidation number of a compound is essentially a meaningless phrase.