The answer is 7
The oxidation number of xenon in XeF2 is +2. Xenon is less electronegative than fluorine, so the oxidation number of xenon is assigned as +2 in this compound.
The oxidation number of xenon in XeF6 is +6. In this compound, the six fluorine atoms each have an oxidation number of -1, so the oxidation number of xenon is calculated as +6 to balance the overall charge of the compound.
Xe when it is not in a compound has an oxidation number of 0
The oxidation number of xenon (Xe) in XeO6 is +8. This is because oxygen generally has an oxidation number of -2, and there are 6 oxygen atoms in XeO6 which gives a total charge of -12. In XeO6, the overall charge is 0, so the oxidation number of xenon must be +8 to balance the charges.
Xenon is a noble gas and typically has an oxidation state of 0 in its elemental form. However, xenon can form compounds where it exhibits positive oxidation states such as +2, +4, +6, or +8.
The oxidation number of xenon in XeF2 is +2. Xenon is less electronegative than fluorine, so the oxidation number of xenon is assigned as +2 in this compound.
The oxidation number of xenon in XeF6 is +6. In this compound, the six fluorine atoms each have an oxidation number of -1, so the oxidation number of xenon is calculated as +6 to balance the overall charge of the compound.
Xe when it is not in a compound has an oxidation number of 0
The oxidation number of xenon (Xe) in XeO6 is +8. This is because oxygen generally has an oxidation number of -2, and there are 6 oxygen atoms in XeO6 which gives a total charge of -12. In XeO6, the overall charge is 0, so the oxidation number of xenon must be +8 to balance the charges.
Xenon is a noble gas and typically has an oxidation state of 0 in its elemental form. However, xenon can form compounds where it exhibits positive oxidation states such as +2, +4, +6, or +8.
There is no such thing as that, oxidation state (number) refers to the "state" of the elements in the compund.
The oxidation state of xenon (Xe) in XeOF4 is +6. This is because oxygen typically has an oxidation state of -2, so in XeOF4 with four oxygen atoms, the xenon must have an oxidation state of +6 to balance the charges.
2, 4 and 6.
The oxidation number of xenon (Xe) in H4XeO6 is +4. This is because hydrogen (H) is typically assigned an oxidation number of +1, and oxygen (O) is typically assigned an oxidation number of -2. By adding up the oxidation numbers for each element in the compound, it must equal the charge of the compound, which is 0 in this case.
Stable xenon fluorides have an even number of fluorine atoms because xenon is in the +2 oxidation state when it forms these compounds. This means it can accept a maximum of 8 valence electrons from fluorine atoms to complete its valence shell, leading to the formation of compounds with an even number of fluorine atoms.
1.what is the oxidation state in xenon in HXeO4- and ... xenon is +7. As= +3 ... Xe = +7. As = +3 ... Except when highly electropositive elements are involved
54 protons in the element Xenon. Xenon has an atomic number of 54 and since the atomic number= number of protons there are 54 protons in xenon.