The oxidation state of an individual sulfur atom in SO4 is +6. In the sulfate ion (SO4^2-), each oxygen atom has an oxidation state of -2, for a total of -8. Since the overall charge of the sulfate ion is -2, the sulfur atom must have an oxidation state of +6 to balance out the charge.
In SO3^2-, sulfur has an oxidation state of +4 (Sulfur's typical oxidation state is +6 and each oxygen has an oxidation state of -2, so the total charge of the ion of -2 corresponds to sulfur being in a +4 oxidation state).
The oxidation state of sulfur in MgSO4 is +6. This is because magnesium has an oxidation state of +2 and oxygen typically has an oxidation state of -2, so the overall compound must have a net charge of 0, leading to sulfur having an oxidation state of +6 to balance the charges.
The oxidation state of sulfur in SO3 is +6. Each oxygen atom has an oxidation state of -2, and since the overall charge of SO3 is 0, the oxidation state of sulfur must be +6 to balance out the charges.
The oxidation state of an individual sulfur atom in BaSo4 is +6.
If you mean SO3^-2 (the sulfite anion), then S has an oxidation number of 4+, since each O atom is 2-. In sulfur trioxide, SO3, the S atom has an oxidation number of 6+.
In SO3^2-, sulfur has an oxidation state of +4 (Sulfur's typical oxidation state is +6 and each oxygen has an oxidation state of -2, so the total charge of the ion of -2 corresponds to sulfur being in a +4 oxidation state).
The oxidation state of sulfur in MgSO4 is +6. This is because magnesium has an oxidation state of +2 and oxygen typically has an oxidation state of -2, so the overall compound must have a net charge of 0, leading to sulfur having an oxidation state of +6 to balance the charges.
The oxidation state of an individual sulfur atom in BaSo4 is +6.
The oxidation state of sulfur in SO3 is +6. Each oxygen atom has an oxidation state of -2, and since the overall charge of SO3 is 0, the oxidation state of sulfur must be +6 to balance out the charges.
If you mean SO3^-2 (the sulfite anion), then S has an oxidation number of 4+, since each O atom is 2-. In sulfur trioxide, SO3, the S atom has an oxidation number of 6+.
The oxidation state of sulfur in SO4^2- is +6. This is because oxygen typically has an oxidation state of -2, and there are 4 oxygen atoms in SO4^2-. Since the overall charge of the ion is -2, the oxidation state of sulfur must be +6 to balance the charges.
Since the total molecule must have zero net oxidation state and there are two oxygen atoms but only one sulfur atom, the sulfur must have oxidation state +4.
In this ion the oxidation state of sulfur is 6+ and the oxidation state of each oxygen is 2-
The sulfate ion is SO42 -. The oxidation state of the sulfur is +6 (work it out!); therefore, the ion is more properly named the sulfate(VI) ion. The sulfite ion is SO32-. The oxidation state of the sulfur is +4.
Sulfur has an oxidation state of +4 in SO3^2-. Each oxygen atom has an oxidation state of -2.
The oxidation state of an atom is the charge it would have if all the shared electrons were assigned to the more electronegative atom. In this case, the oxidation state of each carbon atom in CH3S-SCH3 is +2, as each carbon is bonded to three hydrogen atoms and one sulfur atom, which is more electronegative than carbon. The sulfur atom in the middle has an oxidation state of -2, as it is bonded to two carbon atoms and has two lone pairs of electrons.
The oxidation state of an individual nitrogen atom in CaCO3 is +4. In CaCO3, nitrogen is present in the carbonate ion (CO3)2-, and since each oxygen atom in the carbonate ion has an oxidation state of -2, the carbon atom must have an oxidation state of +4 to balance the charge.