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Which element undergoes Oxidation in k2cro4 na2so3 hcl-kcl na2so4 crcl3 h2o?
Chromium undergoes oxidation in the given chemical equation. In this reaction, chromium changes from a +6 oxidation state to a +3 oxidation state, indicating that it has lost electrons and undergone oxidation.
What is the oxidation number of O in the compound Na2SO4?
The oxidation number of oxygen (O) in most compounds, including sulfate (SO4), is typically -2. In Na2SO4, sodium (Na) has an oxidation number of +1. To calculate the oxidation number of oxygen in the compound, you would use the equation: 2(oxidation number of Na) + oxidation number of S + 4(oxidation number of O) = 0. By plugging in the known values, you can solve for the oxidation number of oxygen in Na2SO4.
What is the oxidation number of S in Na2SO4?
The oxidation number of S in Na2SO4 is +6. This is because Na has an oxidation number of +1 and O has an oxidation number of -2. By setting up and solving an equation, we find that the oxidation number of S must be +6 to balance the charges in the compound.
What is the oxidation state of calcium hydride?
The oxidation state of calcium in calcium hydride is +2, as calcium typically forms ionic compounds with a +2 oxidation state.
What is the oxidation state of zinc in diethylzinc?
Zinc is in oxidation state +2 and oxygen in oxidation state -2. Zinc Oxide itself has not net charge/oxidation state.
Which element undergoes Oxidation in k2cro4 na2so3 hcl-kcl na2so4 crcl3 h2o?
Chromium undergoes oxidation in the given chemical equation. In this reaction, chromium changes from a +6 oxidation state to a +3 oxidation state, indicating that it has lost electrons and undergone oxidation.
What is the oxidation number of O in the compound Na2SO4?
The oxidation number of oxygen (O) in most compounds, including sulfate (SO4), is typically -2. In Na2SO4, sodium (Na) has an oxidation number of +1. To calculate the oxidation number of oxygen in the compound, you would use the equation: 2(oxidation number of Na) + oxidation number of S + 4(oxidation number of O) = 0. By plugging in the known values, you can solve for the oxidation number of oxygen in Na2SO4.
What is the oxidation number of S in Na2SO4?
The oxidation number of S in Na2SO4 is +6. This is because Na has an oxidation number of +1 and O has an oxidation number of -2. By setting up and solving an equation, we find that the oxidation number of S must be +6 to balance the charges in the compound.
Oxidation state of chloride?
The oxidation state of chloride (Cl) is -1. As a halogen, chloride is usually found with an oxidation state of -1 in most compounds.
What is Ca element to its oxidation state.?
The oxidation state of calcium is +2.
What is carbons oxidation state of methanol?
The oxidation state of carbon in methanol (CH3OH) is +2. This is because oxygen has an oxidation state of -2 and hydrogen has an oxidation state of +1, so the carbon must have an oxidation state of +2 to balance the charges in the molecule.
What is the oxidation state of Ca2?
2 oxidation state
What is the oxidation state of oxygen in H2O2?
O = -2 oxidation state H = +1 oxidation state
What is the oxidation state of calcium hydride?
The oxidation state of calcium in calcium hydride is +2, as calcium typically forms ionic compounds with a +2 oxidation state.
What is the oxidation of SO2?
S = +4 oxidation state O = -2 oxidation state
What is the oxidation state of cisplatin?
Platinum is connected to two anionic Chloride ligands and two neutral Ammine ligands Platinum = +2 oxidation state Chlorine = -1 oxidation state Nitrogen = -3 oxidation state Hydrogen = +1 oxidation state
What is the oxidation state of zinc in diethylzinc?
Zinc is in oxidation state +2 and oxygen in oxidation state -2. Zinc Oxide itself has not net charge/oxidation state.
