This is a perfect example of why we have to be so careful about which letters are upper case and which are lower. No stands for nobelium, but as you have also written cl, which should be Cl, I suspect you don't mean nobelium chloride, but NOCl, nitrosyl chloride. If it were NoCl, then the N alone would be meaningless, and the nobelium would have an oxidation state of +1. In NOCl, the nitrogen has an oxidation state of +3.
The oxidation state of nitrogen (N) in nitric acid (HNO3) is +5. This is because hydrogen has an oxidation state of +1 in compounds, and oxygen usually has an oxidation state of -2. Since there are three oxygen atoms with a total oxidation state of -6 and one hydrogen atom with an oxidation state of +1, the nitrogen atom must have an oxidation state of +5 to balance out the charges and make the molecule neutral.
The oxidation number of nitrogen in nitric acid (HNO3) is +5.
-3
In NH4F, nitrogen has an oxidation state of -3, hydrogen has an oxidation state of +1, and fluorine has an oxidation state of -1.
For nitrogen in HNO3 it is '5'. To calculate oxidation numbers. Use oxygen as the stabndard at '-2' -2 x 3 = -6 is the oxygen moiety. Since hydrogen only oxides to '+1' as H^(+). Create a little sum +1 +N - 6 = 0 To balance then N must be '+5'.
The oxidation state of the nitrogen atom in HNO3 is +5. This is because oxygen is typically assigned an oxidation state of -2, and hydrogen is +1. In HNO3, the total oxidation states of the hydrogen and oxygen atoms sum to zero, leaving nitrogen with an oxidation state of +5 to balance the charge.
The oxidation state of nitrogen in HNO3 is +5 because oxygen is assigned an oxidation state of -2 and hydrogen is assigned an oxidation state of +1. The sum of the oxidation states must equal the overall charge of the molecule (zero in this case for a neutral compound).
The oxidation state of nitrogen (N) in nitric acid (HNO3) is +5. This is because hydrogen has an oxidation state of +1 in compounds, and oxygen usually has an oxidation state of -2. Since there are three oxygen atoms with a total oxidation state of -6 and one hydrogen atom with an oxidation state of +1, the nitrogen atom must have an oxidation state of +5 to balance out the charges and make the molecule neutral.
The oxidation number of nitrogen in nitric acid (HNO3) is +5.
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No. HNO3 already has hydrogen and nitrogen in their highest possible oxidation states.
Nitrogen can exist in oxidation states ranging from -3 to +5. Some common nitrogen compounds with different oxidation states include ammonia (NH3) in the -3 oxidation state, nitric oxide (NO) in the +2 oxidation state, nitrogen dioxide (NO2) in the +4 oxidation state, and nitric acid (HNO3) in the +5 oxidation state.
Nitrogen(II) oxide can be produced by oxidation of NO, dehydration of HNO3, thermal decomposition of nitrates etc.
In NH4F, nitrogen has an oxidation state of -3, hydrogen has an oxidation state of +1, and fluorine has an oxidation state of -1.
For nitrogen in HNO3 it is '5'. To calculate oxidation numbers. Use oxygen as the stabndard at '-2' -2 x 3 = -6 is the oxygen moiety. Since hydrogen only oxides to '+1' as H^(+). Create a little sum +1 +N - 6 = 0 To balance then N must be '+5'.
The oxidation state of NO is +1. This is because nitrogen is in Group 15 of the periodic table and typically has an oxidation state of -3. In NO, oxygen is more electronegative than nitrogen, causing nitrogen to have a formal oxidation state of +1 to balance the charge.
In KNO3, the nitrogen atom has an oxidation state of +5. This is because potassium (K) is in Group 1 and has an oxidation state of +1, and oxygen (O) is in Group 6 and has an oxidation state of -2. To balance the charges, nitrogen must have an oxidation state of +5.