In H3PO3 each H is 1+ for a total of 3+. Each O is 2- for a total of 6-. So, there is 3+ and 6- giving a net of 3-. In order to make the molecule neutral, P must have an oxidation state of 3+.
The oxidation state of Rhodium (Rh) in the complex (PPh3)3RhCl is +1. This is because each triphenylphosphine ligand (PPh3) contributes -1 charge (-3 total), and the chloride ligand (Cl) contributes -1 charge. Since the overall charge of the complex is neutral, the oxidation state of Rh is +1.
When calculating oxidation states of compounds containing PPh3 (triphenylphosphine), each phenyl group (Ph) is considered electrically neutral and contributes zero charge. Therefore, the charge of PPh3 is equal to the charge of the phosphorus atom in the compound. Phosphorus typically has an oxidation state of +3 in PPh3, making the overall charge of PPh3 neutral.
The oxidation state of calcium in calcium hydride is +2, as calcium typically forms ionic compounds with a +2 oxidation state.
Zinc is in oxidation state +2 and oxygen in oxidation state -2. Zinc Oxide itself has not net charge/oxidation state.
This oxidation state is 1.
The oxidation state of Rhodium (Rh) in the complex (PPh3)3RhCl is +1. This is because each triphenylphosphine ligand (PPh3) contributes -1 charge (-3 total), and the chloride ligand (Cl) contributes -1 charge. Since the overall charge of the complex is neutral, the oxidation state of Rh is +1.
When calculating oxidation states of compounds containing PPh3 (triphenylphosphine), each phenyl group (Ph) is considered electrically neutral and contributes zero charge. Therefore, the charge of PPh3 is equal to the charge of the phosphorus atom in the compound. Phosphorus typically has an oxidation state of +3 in PPh3, making the overall charge of PPh3 neutral.
To determine the number of electrons in the complex Cr(n5-C5H5)(CO)2(PPh3), we can apply the 18-electron rule. Chromium (Cr) in the zero oxidation state contributes 6 electrons. Each CO ligand donates 2 electrons (total of 4 from 2 CO), and the PPh3 ligand contributes 2 electrons. The n5-C5H5 (cyclopentadienyl) ligand donates 5 electrons. Thus, the total electron count is 6 (Cr) + 4 (from CO) + 2 (from PPh3) + 5 (from n5-C5H5) = 17 electrons.
The oxidation state of chloride (Cl) is -1. As a halogen, chloride is usually found with an oxidation state of -1 in most compounds.
The oxidation state of calcium is +2.
The oxidation state of carbon in methanol (CH3OH) is +2. This is because oxygen has an oxidation state of -2 and hydrogen has an oxidation state of +1, so the carbon must have an oxidation state of +2 to balance the charges in the molecule.
2 oxidation state
O = -2 oxidation state H = +1 oxidation state
The oxidation state of calcium in calcium hydride is +2, as calcium typically forms ionic compounds with a +2 oxidation state.
S = +4 oxidation state O = -2 oxidation state
Platinum is connected to two anionic Chloride ligands and two neutral Ammine ligands Platinum = +2 oxidation state Chlorine = -1 oxidation state Nitrogen = -3 oxidation state Hydrogen = +1 oxidation state
Zinc is in oxidation state +2 and oxygen in oxidation state -2. Zinc Oxide itself has not net charge/oxidation state.