Oxidation states for Na2Cr2O7 are
Na is 1+
Cr is 6+
O is 2-
+1 for Na, +6 for Cr and -2 for each O
Na: 1+
Cr: 6+
O: 2-
This value is 6+.
+6
Cr= 6+
Na2Cr2O7 Sodium always has ox. number = 1, and oxygen = -2. Therefore you got 2x1 = 2 for sodium, and 7*(-2) = -14 for oxygen. 2 + 2*x = 14 x = 6
H = +1 oxidation states S = -2 oxidation states
red-orange
3 Oxidation states: 0, 1 and 2
Yes
Na2Cr2O7 Sodium always has ox. number = 1, and oxygen = -2. Therefore you got 2x1 = 2 for sodium, and 7*(-2) = -14 for oxygen. 2 + 2*x = 14 x = 6
Sodium dichromate has the formula Na2Cr2O7.
H = +1 oxidation states S = -2 oxidation states
0, 1 and 2 oxidation states
Na2Cr2O7
red-orange
Oxidation number is oxidation states of an element. It can be positive or negative.
0 and 1 oxidation states
3 Oxidation states: 0, 1 and 2
Green in its II and III oxidation states and orange in its VI oxidation state.
Na2Cr2O7
Yes