KNO3
The chemical equation for the reaction between glucose (C6H12O6) and potassium nitrate (KNO3) is: C6H12O6 + 6KNO3 → 6KOH + 6CO2 + 6N2 + 6H2O.
3 K2Cr2O7 + 2 (NH4)3PO4 ------------3 (NH4)2Cr2O7 + 2 K3PO4
Lets see... assuming that they're both aqueous and can be dissociated... 3Mg(NO3)2 + 2K3PO4 --> Mg3(PO4)2 + 6KNO3 would be my guess First two, again, I'm assuming to be aqueous, the KNO3 is aqueous, and Mg3(PO4)2 would be the precipitate, or solid. Hope this helped!
The solubility of barium is somewhat mixed---it can be soluble with notoriously insoluble things like hydroxide, and it can be insoluble with other somewhat insoluble anions like sulfate. However, chromate is one anion that is almost always insoluble unless it is paired with an alkali metal. So mixing these two compounds will give you a BaCrO4 precipitate.
the chemical equation when Chromium 3 reacts with sodium hydroxide is as follows.Cr(H2O)6]3+(aq) + 6OH–(aq)==> [Cr(OH)6]3–(aq) + 6H2O(l)this is the ionic equation with hydrixide.
The chemical equation for the reaction between glucose (C6H12O6) and potassium nitrate (KNO3) is: C6H12O6 + 6KNO3 → 6KOH + 6CO2 + 6N2 + 6H2O.
Strontium Nitrate: Sr(NO3)2Potassium Phosphate: K3PO4
3 K2Cr2O7 + 2 (NH4)3PO4 ------------3 (NH4)2Cr2O7 + 2 K3PO4
The balanced equation for this reaction is: 2K3PO4 + 3Al(NO3)3 -> 6KNO3 + AlPO4. This indicates that 2 moles of potassium phosphate react with 2 moles of aluminum nitrate to produce 6 moles of potassium nitrate.
Lets see... assuming that they're both aqueous and can be dissociated... 3Mg(NO3)2 + 2K3PO4 --> Mg3(PO4)2 + 6KNO3 would be my guess First two, again, I'm assuming to be aqueous, the KNO3 is aqueous, and Mg3(PO4)2 would be the precipitate, or solid. Hope this helped!
The reaction between potassium carbonate and calcium nitrate will result in the formation of potassium nitrate and calcium carbonate. The balanced chemical equation is: K2CO3 + Ca(NO3)2 -> 2KNO3 + CaCO3.
The solubility of barium is somewhat mixed---it can be soluble with notoriously insoluble things like hydroxide, and it can be insoluble with other somewhat insoluble anions like sulfate. However, chromate is one anion that is almost always insoluble unless it is paired with an alkali metal. So mixing these two compounds will give you a BaCrO4 precipitate.
the chemical equation when Chromium 3 reacts with sodium hydroxide is as follows.Cr(H2O)6]3+(aq) + 6OH–(aq)==> [Cr(OH)6]3–(aq) + 6H2O(l)this is the ionic equation with hydrixide.
There are two possible products when solutions of:...lead nitrate, Pb(NO3)2, and potassium phosphate, K3PO4, are combined.Step 1: To determine the products "swap" the cations:...potassium nitrate ...and...lead phosphateStep 2: Write the balanced "molecular" equation:3 Pb(NO3)2 + 2 K3PO4Pb3(PO4)2 + 6 KNO3Step 3: Classify each of the substances as Soluble (sol) or Not Soluble (ns):3Pb(NO3)2+2K3PO4Pb3(PO4)2+6KNO3solsolnssolStep 4: Dissociate all soluble salts, and strong acids. Leave together all "not soluble" salts and weak acids or bases:3 Pb2+ (aq) + 6 NO3- (aq) + 6K+ (aq) + 2 PO43- (aq) Pb3(PO4)2 (s) + 6 K+ (aq) + 6 NO3- (aq)Step 5: Cross out "spectator ions", ones that appear on both sides of the reaction (these ions do not participate in the chemistry) and rewrite the "net" reaction using the smallest possible coefficients.3 Pb2+(aq) + 2PO43-(aq) Pb3(PO4)2 (s)
Na3 PO4 + Ba (NO3)2 Þ Ba3 (PO4)2 + Na NO3 Balance Equation: Na= 3 6 ÞNa= 1 6 P= 1 2 ÞP=2 O= 10 18 22 26 ÞO= 11 26 Ba= 1 3 ÞBa=3 N= 2 6 ÞN= 1 6 Na3 PO4 + Ba (NO3)2 Þ Ba3 (PO4)2 + Na NO3 Na3 PO4 + 3Ba (NO3)2 Þ Ba3 (PO4)2 +Na NO3 Na3 PO4 + 3Ba (NO3)2 Þ Ba3 (PO4)2 +6Na NO3 2Na3 PO4 + 3Ba (NO3)2 Þ Ba3 (PO4)2 +6Na NO3