The ph. for this 1M Na2C4H2O4 solution can be found using the kA and the equation pH = pKa + log([base]/[acid]) This salt Na2C4H2O4 is going to increase the concentration of base in the solution.
Its depends on the molar concentration (how much is dissolved per liter of water). A 1M solution has a pH of 14, a 0.1M solution has a pH of 14 and so on until a pH of about 7.
- log(1 M propanoic acid) = 0 pH ========( remember, acids may register below scale )
In a 1M ammonia solution (my guess is 17g/L), about 0.42% of the ammonia is converted to ammonium (my guess is 0.07 g/L), equivalent to a pH of 11.63.
The pH of ammonia solution is about 11. In a 1M ammonia solution (my guess is 17g/L), about 0.42% of the ammonia is converted to ammonium (my guess is 0.07 g/L), equivalent to a pH of 11.63.
"Ammonia", NH3, is a fairly strong base having at 1M concentration in aqueous solution a pH of 11.6
The pH depends on the concentration (how much is dissolved in a given volume of water) Since it is a strong monoprotic acid the pH equals the negative logarithm of its molar concentration. A 1M solution has a pH of 0 a .1M solution has a pH of 1 and so on until a pH of about 7.
Its depends on the molar concentration (how much is dissolved per liter of water). A 1M solution has a pH of 14, a 0.1M solution has a pH of 14 and so on until a pH of about 7.
- log(1 M propanoic acid) = 0 pH ========( remember, acids may register below scale )
10 mM Tris pH 7.5 and 1mM EDTA pH 8.0 For 1 L : 10 mL of 1M Tris-Cl pH 7.5 and 2 mL of 500mM EDTA pH 8.0
In a 1M ammonia solution (my guess is 17g/L), about 0.42% of the ammonia is converted to ammonium (my guess is 0.07 g/L), equivalent to a pH of 11.63.
The pH of ammonia solution is about 11. In a 1M ammonia solution (my guess is 17g/L), about 0.42% of the ammonia is converted to ammonium (my guess is 0.07 g/L), equivalent to a pH of 11.63.
"Ammonia", NH3, is a fairly strong base having at 1M concentration in aqueous solution a pH of 11.6
pH = -log[H+]That is, the pH of a solution is the negative log of the concentration of hydrogen atoms. The concentration of hydrogen atoms must be in units of Molarity, or moles per liter. In order to determine the pH of a solution containing 1 mole of HCl, you must also know the volume of the solution.I am assuming the question is: What is the pH of 1M HCl, and not 1 mole. 1 mole HCl is simply the mass in grams of the atomic weight of H and Cl: 1+35.45=36.45. This is not a unit of concentration and if that is truly the question then the answer is undefined.Molarity on the other hand, and other units of concentration, are completely independent of total amount of solution (volume or mass): molarity (M)= moles/LitersHCl is a strong acid. This means that all of those acid hydrogens are releasing into solution and therefore the calculation is very simple:pH of strong acid= -log[H+] 1M HCl= 1M[H+] + 1M[Cl-] pH=-log[1]= 0
This depends on its concentration. In a 1M ammonia solution (my guess is 17g/L), about 0.42% of the ammonia is converted to ammonium (my guess is 0.07 g/L), equivalent to a pH of 11.63.
the pH of ammonia is about 11.6 In a 1M ammonia solution (my guess is 17g/L), about 0.42% of the ammonia is converted to ammonium (my guess is 0.07 g/L), equivalent to a pH of 11.63.
THE PH VALUE ACIDIC SOLUTION VARIOUS FROM 0-6.9, WHILE THE BASIC SOLUTION VARIOUS FROM 7.1-1.4. THUS ,OUT OF HCL AND NaOH WILL HIGHER PH VALUE
There is no single substance with any given pH. pH Depends on both the strength of an acid or base and how much of it is dissolved in a given volume of water. A 1M solution of an alkali metal hydroxide will yield such a pH, but a higher concentration of a weaker base may do the same.