The ph. for this 1M Na2C4H2O4 solution can be found using the kA and the equation pH = pKa + log([base]/[acid]) This salt Na2C4H2O4 is going to increase the concentration of base in the solution.
The pH of a 1M propanoic acid solution would be around 2.98. Propanoic acid is a weak acid with a pKa value of 4.87, so at 1M concentration, it would partially dissociate in water to release hydronium ions, resulting in an acidic pH.
The pH of sulfuric acid depends on its concentration. For a 1M solution, the pH would be around 0.3, indicating it is highly acidic.
The pH of a solution of KNO3 (potassium nitrate) will depend on the concentration of the solution. At a concentration of 1M, the pH of a solution of KNO3 is around 7, making it neutral. If the concentration is higher or lower, the pH may deviate slightly from neutral.
The pH of H3PO4 (phosphoric acid) depends on its concentration. For a 1M solution, the pH would be around 0.91. Since phosphoric acid is a weak acid that can donate three protons, its pH decreases with increasing concentration due to the dissociation of H+ ions.
Let's see. NaOH + HCl = NaCl + H2O The usual salt ( NaCl ) and water.
The pH of a 1M propanoic acid solution would be around 2.98. Propanoic acid is a weak acid with a pKa value of 4.87, so at 1M concentration, it would partially dissociate in water to release hydronium ions, resulting in an acidic pH.
The pH of sulfuric acid depends on its concentration. For a 1M solution, the pH would be around 0.3, indicating it is highly acidic.
The pH depends on the concentration (how much is dissolved in a given volume of water) Since it is a strong monoprotic acid the pH equals the negative logarithm of its molar concentration. A 1M solution has a pH of 0 a .1M solution has a pH of 1 and so on until a pH of about 7.
10 mM Tris pH 7.5 and 1mM EDTA pH 8.0 For 1 L : 10 mL of 1M Tris-Cl pH 7.5 and 2 mL of 500mM EDTA pH 8.0
The pH of a solution of KNO3 (potassium nitrate) will depend on the concentration of the solution. At a concentration of 1M, the pH of a solution of KNO3 is around 7, making it neutral. If the concentration is higher or lower, the pH may deviate slightly from neutral.
The pH of H3PO4 (phosphoric acid) depends on its concentration. For a 1M solution, the pH would be around 0.91. Since phosphoric acid is a weak acid that can donate three protons, its pH decreases with increasing concentration due to the dissociation of H+ ions.
Let's see. NaOH + HCl = NaCl + H2O The usual salt ( NaCl ) and water.
pH = -log[H+]That is, the pH of a solution is the negative log of the concentration of hydrogen atoms. The concentration of hydrogen atoms must be in units of Molarity, or moles per liter. In order to determine the pH of a solution containing 1 mole of HCl, you must also know the volume of the solution.I am assuming the question is: What is the pH of 1M HCl, and not 1 mole. 1 mole HCl is simply the mass in grams of the atomic weight of H and Cl: 1+35.45=36.45. This is not a unit of concentration and if that is truly the question then the answer is undefined.Molarity on the other hand, and other units of concentration, are completely independent of total amount of solution (volume or mass): molarity (M)= moles/LitersHCl is a strong acid. This means that all of those acid hydrogens are releasing into solution and therefore the calculation is very simple:pH of strong acid= -log[H+] 1M HCl= 1M[H+] + 1M[Cl-] pH=-log[1]= 0
The pH of a 1N HCl solution can be calculated using the formula pH = -log[H+], where [H+] is the concentration of H+ ions in the solution. For a 1N solution of HCl, the concentration of H+ ions will be 1M, so the pH will be -log(1) = 0.
1m*1m*0.5m=0.5m3
pH values depend on the concentration of acidsolutionfor eg.0.02 M HF has pH=2.47
The formula for the area of a rectangle is A=LW; L- length and W- width. A=1m x 1m= 1m².