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In aqueous solution, ammonia deprotonates a small fraction of the water to give ammonium and hydroxide according to the following equilibrium:

NH3 + H2O <---> NH4 (aq) + OH (aq)

In a 1M ammonia solution (my guess is 17g/L), about 0.42% of the ammonia is converted to ammonium (my guess is 0.07 g/L), equivalent to a pH of 11.63.

The base ionization constant is Kb = [NH4+][OH-]/[NH3] = 1.8×10−5

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