ok so 0.3M means 0.3 moles/Liter
so you need to set up a proportion to find the number of moles of NH3 in 50mL not 1000mL
so you do: 0.3mol/1000mL = x mol/50mL
x=0.000015
so the [NH3] is 1.5x10^-5
NH3 is a weak base so it won't dissociate completely so you need its Kb to find the [H+] it will release
pH= -log[H+]
Household ammonia has a pH of 11.5 to 12.5
Ammonia is a basic gas. It shows high ph if it is dissolved in water.
VInegar has the low ph. Ammonia has the high ph.
The pH of ammonia solution is about 11. In a 1M ammonia solution (my guess is 17g/L), about 0.42% of the ammonia is converted to ammonium (my guess is 0.07 g/L), equivalent to a pH of 11.63.
Ammonia has a pH level around 11-12, making it alkaline. This means it is a base on the pH scale, with values above 7 indicating alkalinity.
Household ammonia has a pH of 11.5 to 12.5
Ammonia is a basic gas. It shows high ph if it is dissolved in water.
VInegar has the low ph. Ammonia has the high ph.
The pH of aqueous ammonia depends on its concentration, with higher concentrations leading to a higher pH. In general, the pH of an ammonia solution will be alkaline, typically ranging from 11-13. The pounds of ammonia per gallon of water will affect the concentration and thus the pH of the solution.
The pH of ammonia solution is about 11. In a 1M ammonia solution (my guess is 17g/L), about 0.42% of the ammonia is converted to ammonium (my guess is 0.07 g/L), equivalent to a pH of 11.63.
Ammonia has a pH level around 11-12, making it alkaline. This means it is a base on the pH scale, with values above 7 indicating alkalinity.
Ammonia is a substance that when dissolved causes a solution to be basic (pH higher than 7) however without knowing the concentration of the ammonia in solution, it is impossible to determine the pH.
5.7
No. One molar ammonia has a pH of around 11.
The pH of ammonia cleaner is typically around 11-12, making it alkaline.
This depends on its concentration.Household ammonia has a pH of 11.5 at a molarity of 3.16 x 10-12(-12 is the exponent!)
To determine the pH of the solution after adding 30 ml of 15M NaOH to 50 ml of HOAc, we need to calculate the moles of each component to find the excess OH- ions. Then, we can determine the resulting concentration of hydroxide ions and use the Kb value of HOAc to calculate the OH- concentration, which can be used to calculate pOH and finally pH using the relation pH = 14 - pOH.