It depends upon the amount of strong acid that you are using.... in a titration process the pH value initially starts off basic in the beaker.. and doesn't change rapidly until all of the base has reacted with the acid to from water and precipitate ... after all of the weak base has reacted with the acid.. the final PH value is in the acid range i.e 1-7
The complete neutralization of potassium hydroxide (KOH) with hydrochloric acid (HCl) results in the formation of potassium chloride (KCl) and water (H2O). The balanced chemical equation for this reaction is: KOH + HCl -> KCl + H2O.
KOH + HCl -> KCl + H2O This is a neutralization reaction. You know because it produces water and a salt.
This reaction gives ammonium chloride as the product.
This is a neutralization reaction where an acid (HCl) reacts with a base (KOH) to form a salt (KCl) and water (H2O). The reaction is exothermic and the products are typically in solution.
The balanced chemical equation for the neutralization of triethylamine (C6H15N) with hydrochloric acid (HCl) is: C6H15N + HCl --> C6H16N+Cl-
The complete neutralization of potassium hydroxide (KOH) with hydrochloric acid (HCl) results in the formation of potassium chloride (KCl) and water (H2O). The balanced chemical equation for this reaction is: KOH + HCl -> KCl + H2O.
KOH + HCl -> KCl + H2O This is a neutralization reaction. You know because it produces water and a salt.
This reaction gives ammonium chloride as the product.
This is a neutralization reaction where an acid (HCl) reacts with a base (KOH) to form a salt (KCl) and water (H2O). The reaction is exothermic and the products are typically in solution.
The balanced chemical equation for the neutralization of triethylamine (C6H15N) with hydrochloric acid (HCl) is: C6H15N + HCl --> C6H16N+Cl-
HCl+NaOH, when mixed in equimolar amounts, produces a neutral solution of NaCl.
When 100cm3 of 1.0 molar of sodium hydoxide solution at 200oc was added to 100cm3of1.0 molar of HCL solution at 200oc,then the temperature of HCL rose to 26.8oc.calculate the standard heat of neutralisation?(Given that the specific heat capacity of water is 4.2KJg-1k-1)
The balanced equation for the neutralization reaction between hydrochloric acid (HCl) and lithium hydroxide (LiOH) is: HCl + LiOH -> LiCl + H2O
This equation can be written as NaOH (aq) + HCl (aq) -> NaCl (aq) + H2O if the reaction occurs in aqueous solution. The only actual chemical reaction is between the aquated hydroxide and hydrogen ions, the chloride and sodium ions being "spectators" only.
Hydrochloric acid (HCl) is a strong acid, while acetic acid (HC2H3O2) is a weaker acid. In solution, HCl will dissociate completely into H+ and Cl- ions, while HC2H3O2 will only partially dissociate. This results in a higher concentration of H+ ions in HCl solution compared to HC2H3O2 solution at the same concentration.
HCl or hydrochloric acid will react with NaOH (sodium hydroxide) in a netralisation reaction. HCl is a strong acid and NaOH is a strong base or alkalai. The resultant solution will be warm/hot due to the exothermic reaction taking place. This is an aggressive reaction if the materials are concentrated. HCl + NaOH --> H2O + NaCl
No, a 38% HCl solution is not the same as a 12N HCl solution. The concentration of a solution is based on the amount of solute dissolved in a specific volume of solvent. A 38% HCl solution means there is 38 grams of HCl in 100 mL of solution, while a 12N HCl solution means there are 12 moles of HCl in one liter of solution.