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It depends on the concentration. pH is the negative log of the concentration of H+ atoms in a solution (measured it molarity, mol/L). Phosphoric acid (H3PO4) has 3 Hs in it, so for every molecule of acid dissolved, there are 3H+ ions.

But Phosphoric acid isn't a strong acid, so it doesn't completely dissolve in water. You can tell whether an acid is strong or not by looking at the number of Os and Hs. If it has 2 more Os than Hs, it is strong.

One must look up how thoroughly the acid dissolves in water. By looking it up on wolframalpha, I find that for every mole of H3PO4

In the solution, 1.06 moles of H+ are present. So if I take the -log1.06, I find the pH of 1M phosphoric acid, which is 1.1.

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13y ago

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How can you find the pH of phosphoric acid that is complelely ionized using the 3 equations?

To find the pH of completely ionized phosphoric acid, first determine the concentration of the hydronium ions (H3O+) by using the molarity of the phosphoric acid solution. Then, calculate the pH using the equation pH = -log[H3O+]. Since phosphoric acid has three dissociable protons, the pH would be dependent on the concentration of H3O+ from the complete ionization of the acid.


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