What is the percent composition of KMnO4?

Answer 1

Potassium permanganate, or KMnO4, has a molar mass of 158g/mol. (39+55+16x4). % composition of K: 39/158=0.247=24.7%. % composition of Mn: 55/158=0.348=34.8%. % composition O: 64/158=0.405=40.5%.

Answer 2

The molar mass of KMnO4 is calculated by adding the molar masses of each element: potassium (K) has a molar mass of approximately 39.10 g/mol, manganese (Mn) has a molar mass of approximately 54.94 g/mol, and oxygen (O) has a molar mass of approximately 16.00 g/mol. Therefore, the molar mass of KMnO4 is approximately 158.04 g/mol. To find the percent composition of KMnO4, divide the molar mass of each element by the molar mass of KMnO4 and multiply by 100. The percent composition of KMnO4 is approximately 24.72% potassium, 34.82% manganese, and 40.46% oxygen.

Answer 3

KMnO4 has a Molar mass of 158.04 g/mol

There are two possibillities:

1. KMnO4 as an oxidizer in acidic media:

MnO4- + 8 H+ + 5e- --> Mn2+ + 4H2O (gained 5 electrons from reductant)

I.e. Eq. wt. of KMnO4 = 158.04/5 = 31.61 grams/equivalent

2. KMnO4 as an oxidizer in basic media:

MnO4- + 2H2O + 3e- --> MnO2(s) + 4OH- (gained 3 electrons)

In which case, Eq. wt. of KMnO4 = 158.04/3 = 52.68 grams/equivalent

Answer 4

The elemental composition of potassium permanganate is:
- oxygen: 40,52 5
- manganese: 34,80%
- potassium: 24,68 %

Answer 5

The molar mass of KMnO4 is 158,034 g.

Answer 6

The percent composition of KMnO4 is:

• Potassium (K) = 20.43%
• Manganese (Mn) = 27.25%
• Oxygen (O) = 52.31%

Answer 7

25% K, 35% Mn, 40% O

Answer 8

The density id 2.703 g/mL