The percent of oxygen in KClO3 is 48.4%. This can be calculated by dividing the molar mass of oxygen in KClO3 (48 g/mol) by the molar mass of KClO3 (122.55 g/mol) and multiplying by 100%.
The atomicity of KClO3 is one, which means that in one molecule of KClO3, there is one atom each of potassium (K), chlorine (Cl), and oxygen (O).
2 grams of Oxygen can be obtained from 5 grams of KClO3 (only if the "CL" means "Cl", which is Chlorine! Remember that only the first letter of the atomic symbol is capitalized.)
To calculate the mass of potassium chlorate containing 40.0g of oxygen, first determine the molar mass of oxygen (16g/mol). Then, use the molecular formula of potassium chlorate (KClO3) to find the oxygen's molar ratio in KClO3 (1:3). Finally, calculate the mass of KClO3 using the molar mass and the molar ratio to find that approximately 186 grams of potassium chlorate contain 40.0g of oxygen.
The chemical equation for converting potassium chlorate (KClO3) into oxygen (O2) is: 2KClO3 (s) -> 2KCl (s) + 3O2 (g). When heated, potassium chlorate decomposes into potassium chloride and oxygen gas.
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
KClO3
The atomicity of KClO3 is one, which means that in one molecule of KClO3, there is one atom each of potassium (K), chlorine (Cl), and oxygen (O).
First calculate the molar mass of the potassium chlorate KClO3 K is 39.1, Cl is 35.45 and O is 16 x 3 =48 The molar mass for one mol is 122.55g/mol The percent composition is the part the oxygen contributed divided by the total molar mass times 100(to convert a decimal to a percent) 48/122.55 x 100 is 39.167% Potassium Chlorate is 39.167 percent oxygen
2KClO3 + heat -> 2KCl + 3O2 14 moles KClO3 (3 mole O2/2 mole KClO3) = 21 moles oxygen made This is a common industrial method of producing oxygen.
O2 is oxygen molecule; KCl is potassium chloride
If potassium chlorate is contaminated with KCl, the experimental percent oxygen would likely be lower than the theoretical value because KCl does not contain oxygen. This contamination would reduce the amount of oxygen available from the potassium chlorate during the reaction, thus lowering the experimental yield of oxygen.
2 grams of Oxygen can be obtained from 5 grams of KClO3 (only if the "CL" means "Cl", which is Chlorine! Remember that only the first letter of the atomic symbol is capitalized.)
Potassium chlorate (KClO3) has 3 oxygen atoms.
3 moles of oxygen are obtained from 2 moles of potassium chlorate.M of KClO3 is 122,55 g, M of O2 is 32, density of oxygen is 1,429 g/L.
No, KClO3 is not the same as potassium chloride. KClO3 is potassium chlorate, a compound that contains potassium, chlorine, and oxygen. Potassium chloride, on the other hand, is a compound that contains only potassium and chlorine.
A 1.80-gram mixture of potassium chlorate, kclo3, and potassium chloride, kcl, was heated until all of the kclo3 had decomposed the liberated oxygen, after drying, occupied 405 ml at 25C when the barometric pressure was 745 torr. This is the problem and the questions were... a. How many moles of O2 were produced? b. What percent of the mixture was KClO3? KCl? Please help!!
To calculate the mass of potassium chlorate containing 40.0g of oxygen, first determine the molar mass of oxygen (16g/mol). Then, use the molecular formula of potassium chlorate (KClO3) to find the oxygen's molar ratio in KClO3 (1:3). Finally, calculate the mass of KClO3 using the molar mass and the molar ratio to find that approximately 186 grams of potassium chlorate contain 40.0g of oxygen.