1. Find the molar mass of the hydrate.
Find the molar mass of the water molecules (18.01528 x # water molecules) and of the anhydrate; add the values together to find the molar mass of the hydrate.
Molar Mass Water + Molar Mass Anhydrate = Molar Mass Hydrate
2. Find the percent of water in hydrate.
Divide the molar mass of water by the molar mass of hydrate; multiply by 100%.
- Mass water
Mass hydrate x 100%
21.7%
The above answer is incorrect.
Find the molar mass (MM) of hydrate (cobalt chloride hexahydrate).
MM CoCl2: 129.8g
+ MM 6H2O: 108.1g
MM CoCl2 x 6H2O: 237.9g
Find the percentage of water in hydrate.
Divide the mass of water lost by the mass of the hydrate (substance before water is removed).
108.1g
237.9g x 100%
Percent water of hydrate is 45.43%
Finding molar mass
# atoms Element A x Atomic Mass Element A = Mass A
# atoms Element B x atomic mass Element B = Mass B
... etc.
Add up all the mass values above and you have molar mass.
Molar Mass CoCl2 * 6H2O = 237.9
1mol CoCl2 6H2O --> 6 mol H2O
6 mol H2O * 18g/1mol = 108g H2O
percent of water =108g H2O/237.9g CoCl2 6H2O * 100% = 45%
CoCl2.6H2O - molecular weight is 237.93
Percentage of water = (6 * 18) / 237.93 = 0.454 or 45.4%
The molar mass of CoCl2.6H2O is 237,93.
But if you thinked to CoCl3 the molar mass is 165,291.
About 63% or less, I think
Dark Blue
The colour become initially purple and after (with more humidity) pink.
Idn!!
CoCl2 cobaltous chloride, a crystalline compound, is blue when dehydrated and a pale rose color when hydrous. One application is the use of cobaltous chloride in sympathetic ink. When the writing is dried in air it is nearly colorless to do absoption by water in the air. When the ink is warmed it becomes bright blue. All the information above was found on dictionary.die.net/cocl2
Cobalt(II) chloride may be a reactant in a chemical reaction.
Yes, CoCl2 * 6H2O is the hexahydrate of the an hydrate CoCl2.
Dark Blue
The colour become initially purple and after (with more humidity) pink.
Idn!!
CoCl2 cobaltous chloride, a crystalline compound, is blue when dehydrated and a pale rose color when hydrous. One application is the use of cobaltous chloride in sympathetic ink. When the writing is dried in air it is nearly colorless to do absoption by water in the air. When the ink is warmed it becomes bright blue. All the information above was found on dictionary.die.net/cocl2
Cobalt(II) chloride may be a reactant in a chemical reaction.
The chemical name is usually "water" for H2O regardless of how many there are. In naming a hydrate such as CuSO4.5H2O we first name the compound before the "dot". Here it is "copper(II) sulfate". Then use the prefix for the number of water molecules attached. Here it is "penta" for five. The "dot" tells us that it is a hydrate. The name of CuSO4.5H2O would be "copper(II) sulfate pentahydrate".
CoCl2.6H2O has 6 water molecules attached as secondary valencies and 2 chlorine atoms are serving as the primary valencies. The secondary valencies are directional in nature and hence they lead to the geometry of it. The geometry of this compound is Octahedral with cobalt showing a coordination no. of 6.
Equation:CoCl2.6H2O + heat --> CoCl2 + 6H2OYou have the mass of CoCl2.6H2O, which is 20g.You know the Mr of CoCl2.6H2O as well:58.93 + 35.5(2) + 6(18)= 237.93gmol-1 (The 18= H2O)You know the formula to calculate the no. of moles:n=mass/Mr, therefore n= 20/237.933 = 0.0841 molesThe ratio of CoCl2.6H2O: CoCl2 is 1:1, therefore CoCl2 has the same number of moles as does CoCl2.6H2O.So you want the mass of CoCl2? Well you havethe the Mr of it and now you have the no. of moles.Mr of CoCl2:58.93 + 35.5(2)= 129.93 (Or you could simply do 237.93 - 6(18) )Since n=mass/Mr you simply rearrange to get mass by itself. Which is:mass= n x MrTherefore the mass ofCoCl2ismass = 0.0841 x 129.93 = 10.92g (Answer)Daniel Hajsadr
It turns into a blue solution of [Cu.6H2O]2+ complex (or hydrated) ions. The blue crystal form of copper sulfate consists of CuSO4.5H2O complex hydrate ion array, the white form is anhydrous CuSO4 (crystal form without H2O)
The equation is 6CO2 + 6H2O --> C6H12O6 the reactants are carbon dioxide and water while the product is glucose.
p4o10 + 6h2o -----> 4h3po4