45.70
The compound NiSO4·7H2O consists of one NiSO4 molecule and seven water molecules. The percentage of water can be calculated by dividing the molar mass of water by the molar mass of the whole compound, and then multiplying by 100. This results in about 37.2% water in NiSO4·7H2O.
The atomic mass of CuSO4 is 159.61 g/mol, and that of 5 H2O is 90.08 g/mol. To find the percentage of water, we calculate (90.08 g/mol / (90.08 g/mol + 159.61 g/mol)) * 100, which is approximately 36.1%. So, the crystal contains around 36.1% water to the nearest tenth.
Yes it is. This is because there are 1000 milligrams in a gram. So 100/1000 is a tenth.
Since a deciliter is one tenth of a liter, a centiliter is one hundredth. This means that there are .1 centiliters in one deciliter.
1 tenth gold typically refers to 1/10th of an ounce of gold. This is a common measurement used to denote smaller quantities of gold in the precious metals market.
72.70
72.70
The relative molecular weight of the compound nickel (II) sulphate heptahydrate NiSO4 7H2O is 280. 86. The total mass of oxygen in the compound is 176 g. Therefore the total percentage of oxygen to the nearest tenth is 60 percent
0.57
0.2
150.0
43.7
44.9
As a percentage 0.452 = 45.2%
0.6
30.4% increase.
percentage to the nearest tenth of a percent = 90.0% % rate: = 45/50 * 100% = 0.90 * 100% = 90.0%