A double replacement reaction takes place when aluminum sulfate reacts with ammonium hydroxide; the precipitate will be aluminum hydroxide (the ammonium sulfate will remain in solution, and we're assuming the reactants were already in aqueous solution.) Most metallic hydroxides are insoluble. The balanced equation for this reaction, showing the appropriate states of matter is:
Al2(SO4)3(aq) + 6NH4OH(aq) --> 3(NH4)2SO4(aq) + 2Al(OH)3(s)
Copper hydroxide is the precipitate.
Together they make ammonium sulfate and water.
The color of the precipitate formed when copper oxide (CuO) reacts with hydrochloric acid (HCl) is typically black or brown. This reaction produces copper chloride (CuCl2) along with water (H2O).
The color of the silver nitrate precipitate obtained is white.
The white precipitate formed in the reaction between BaCl2 and K2CrO4 is BaCrO4 (barium chromate). This precipitate forms because Ba2+ ions from BaCl2 react with CrO4^2- ions from K2CrO4 to produce an insoluble compound that falls out of solution.
A precipitate
I guess it is called as NH4OH
Decomposition
Copper hydroxide is the precipitate.
Together they make ammonium sulfate and water.
The reaction of ammonium hydroxide (NH4OH) with water is generally considered endothermic. When NH4OH dissolves in water, it absorbs heat from the surroundings, leading to a decrease in temperature. This is why you may feel a cooling effect when handling a solution of ammonium hydroxide.
The color of the precipitate formed when copper oxide (CuO) reacts with hydrochloric acid (HCl) is typically black or brown. This reaction produces copper chloride (CuCl2) along with water (H2O).
(Don't forget to balance it) The precipitate here has to be 2NaCl, as Ca(CO3)2 technically dissolves.
The color of the silver nitrate precipitate obtained is white.
The white precipitate formed in the reaction between BaCl2 and K2CrO4 is BaCrO4 (barium chromate). This precipitate forms because Ba2+ ions from BaCl2 react with CrO4^2- ions from K2CrO4 to produce an insoluble compound that falls out of solution.
The chemical equation is:3 NaOH + FeBr3 = 3 NaBr + Fe(OH)3
These compounds will not react. They both contain the same anion, and thus there can be no reaction between them. Consequently, the reactants will remain unchanged.