What is the pressure exerted by 1.2 mol of a gas with a temperature of 20 C and volume of 9.5L?

Answer 1

In this case, pressure is calculated based on the temperature at kelvin, so 16 Celsius is 289 kelvin. Then, you multiply the moles by the dm^3*kPa (in this case 8.31 dm^3*kPa, multiply that by the temperature, and divide by the volume, to get 162 kPa.

Answer 2

PV = nRT
P = nRT/V = (1.2)(0.0821)(293)/9.5
P = 3.04 atmospheres
Units are: P = atmospheres; n = moles; R = L-atm/deg-mole; T= deg K; V = liters

Answer 3

The pressure is 3,037 atmosphere.