Na3(PO4)3 + NiCl2 => ...
the formula is NiCl2
Mn+NiCl2---->MnCl2(aq)+Ni(s)
NiCl2 x 6 H2O Nickel(II) Chloride Hexahydride
8.66 x 10^20 formula units NiCl2 x (1 mol NiCl2 / 6.022x10^23 # atoms NiCl2) x (3 mol Ni and Cl2 / 1 mol NiCl2) = 4.31 x 10^-3 moles of ions
Na2CO3(aq) + NiCl2(aq) --> NiCO3(s) + 2NaCl(aq)
Ni + AlCl3
NiCl2 is nickel chloride
the formula is NiCl2
Mn+NiCl2---->MnCl2(aq)+Ni(s)
NiCl2 x 6 H2O Nickel(II) Chloride Hexahydride
8.66 x 10^20 formula units NiCl2 x (1 mol NiCl2 / 6.022x10^23 # atoms NiCl2) x (3 mol Ni and Cl2 / 1 mol NiCl2) = 4.31 x 10^-3 moles of ions
Na2CO3(aq) + NiCl2(aq) --> NiCO3(s) + 2NaCl(aq)
Formula: NiCl2
ionic
NiCl2
2
This is the correct answer 2HCl(aq) + Ni(s) → NiCl2(aq) + H2(g)