Cu(OH)2 + (NH4)2SO4
The balanced equation for the reaction between copper sulfate (CuSO4) and ammonia (NH3) is CuSO4 + 4NH3 → Cu(NH3)4SO4.
The light blue color of a solution of CuSO4 in water is due to absorption of yellow light by a coordination complex of water and copper cations. When NH3 is added, the water molecules in the coordination complex are replaced by ammonia molecules, and the resulting complex absorbs yellow light more strongly than the original one.
The color of Ni(NH3)6^2+ is violet.
The insoluble product of the reaction between KOH and CuSO4 is copper(II) hydroxide (Cu(OH)2). This can be found by determining the products formed from the reaction between the potassium hydroxide (KOH) and copper sulfate (CuSO4), and then identifying the insoluble compound formed, which is copper(II) hydroxide.
Did you mean Sulfuric acid? H2SO4 + CuSO4 -> H2SO4 + CuSO4 Since both anions are sulfates there will be no reaction as there is no change.
The balanced equation for the reaction between copper sulfate (CuSO4) and ammonia (NH3) is CuSO4 + 4NH3 → Cu(NH3)4SO4.
The balanced equation for the reaction between copper sulfate solution (CuSO4) and ammonia solution (NH3) is: CuSO4 + 4NH3 -> [Cu(NH3)4]SO4
As gaseous ammonia with solid coppersulfate: 2NH3(g) + CuSO4(s) --> Cu(NH3)2SO4(s) With water: [Cu(NH3)2]2+ complex-ions with SO42- ions in aquous solution (deep blue color)
The light blue color of a solution of CuSO4 in water is due to absorption of yellow light by a coordination complex of water and copper cations. When NH3 is added, the water molecules in the coordination complex are replaced by ammonia molecules, and the resulting complex absorbs yellow light more strongly than the original one.
The color of Ni(NH3)6^2+ is violet.
The insoluble product of the reaction between KOH and CuSO4 is copper(II) hydroxide (Cu(OH)2). This can be found by determining the products formed from the reaction between the potassium hydroxide (KOH) and copper sulfate (CuSO4), and then identifying the insoluble compound formed, which is copper(II) hydroxide.
Did you mean Sulfuric acid? H2SO4 + CuSO4 -> H2SO4 + CuSO4 Since both anions are sulfates there will be no reaction as there is no change.
The product in the Haber process is ammonia (NH3).
NH4+ (aq) + OH (aq) ----> NH3 (g) + H2O(l) The product, ammonia, is NH3
CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
Yes, CuSO4 is an electrolyte.