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What is the theoretical rate constant value for hydrolysis of ethyl acetate?
The theoretical rate constant value for the hydrolysis of ethyl acetate is approximately 1.0 x 10^-6 s^-1 at room temperature. This reaction is catalyzed by acid or base, with acid-catalyzed hydrolysis generally being faster. The actual rate constant value may vary depending on the specific conditions of the reaction.
What is the rate constant of a reaction if rate 1 10-2 molLs A is 2 M B is 3 M m 2 and n 1?
The rate law for the reaction is given by Rate = k[A]^m[B]^n. Plugging in the given concentrations and rate into the rate law, we have 10^-2 = k*(2)^2*(3)^1. Solving for k gives k = 10^-2 / (43) = 10^-2 / 12 = 8.33 x 10^-4 L/mols.
When the concentration of a reactant was 0.100 M the rate of the reaction was 8.42 X 106 M s-1 When the concentration of the reactant was doubled to 0.200 M the rate increased to 1.59 X 105 M s1 What?
The reaction is first order with respect to the reactant. The rate constant k can be determined by using the rate equation in the form rate = k [A]. By plugging in the values for rate and concentration at both conditions, you can solve for k. The rate constant k in this case would be 1.59 × 10^3 M^-1 s^-1.
Is the rate of a chemical reaction dependent of temperature?
In general, as temperature rises, so does reaction rate. This is because the rate of reaction is dependent on the collision of the reacting molecules or atoms. As temperature rises, molecules or atoms respond with increased motion, increasing the collision rate, thus increasing the reaction rate.
How many molecules of CH4 are in 2.52 mol of CH4?
Divide 2.52 by molecular mass 16.Then multiply by avagadro constant
What is the rate constant of a reaction if rate 1.5 mol L s A is 1 M B is 3 M m 2 and n 1?
8.3*10^-4
What is the rate constant of a reaction if rate 1 10-2 mol L s A is 2 M B is 3 M m 2 and n 1?
0.5
Why is it necessary to specify the temperature when giving a value for k?
The rate constant, k, varies with temperature, so the temperature at which it has been determined must be given. In general a 10 oC temperature increase will double the rate of a chemical reaction.
What is the theoretical rate constant value for hydrolysis of ethyl acetate?
The theoretical rate constant value for the hydrolysis of ethyl acetate is approximately 1.0 x 10^-6 s^-1 at room temperature. This reaction is catalyzed by acid or base, with acid-catalyzed hydrolysis generally being faster. The actual rate constant value may vary depending on the specific conditions of the reaction.
What is the rate constant of a reaction if rate 0.2 (molL)s A and B are each 3 M m 1 and n 2?
7.4 10-3
What is the rate constant of a reaction if rate 1 x 10-2 (MolL)s A is 2 M B is 3 M m 2 and n 1?
To find the rate constant (k) of the reaction, we can use the rate equation: Rate = k[A]^m[B]^n. Given that the rate is (1 \times 10^{-2} , \text{(mol L)}^{-1} , \text{s}^{-1}), [A] = 2 M, [B] = 3 M, m = 2, and n = 1, we substitute these values into the equation: [ 1 \times 10^{-2} = k \cdot (2^2) \cdot (3^1) ] This simplifies to: [ 1 \times 10^{-2} = k \cdot 4 \cdot 3 \implies 1 \times 10^{-2} = k \cdot 12 ] Solving for k gives: [ k = \frac{1 \times 10^{-2}}{12} \approx 8.33 \times 10^{-4} , \text{(mol L)}^{-1} , \text{s}^{-1} ]
What is constant rate?
A relative rate constant the rate at which a reaction will take place. Ex. V = k [A][B] the constant ,k, is a constant value for the rate of the reaction in said equation.
What is the rate constant of a reaction if rate 1 10-2 molLs A is 2 M B is 3 M m 2 and n 1?
The rate law for the reaction is given by Rate = k[A]^m[B]^n. Plugging in the given concentrations and rate into the rate law, we have 10^-2 = k*(2)^2*(3)^1. Solving for k gives k = 10^-2 / (43) = 10^-2 / 12 = 8.33 x 10^-4 L/mols.
How many atoms of sodium na are in 7 mol of sodium answer in units of atoms?
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
When the concentration of a reactant was 0.100 M the rate of the reaction was 8.42 X 106 M s-1 When the concentration of the reactant was doubled to 0.200 M the rate increased to 1.59 X 105 M s1 What?
The reaction is first order with respect to the reactant. The rate constant k can be determined by using the rate equation in the form rate = k [A]. By plugging in the values for rate and concentration at both conditions, you can solve for k. The rate constant k in this case would be 1.59 × 10^3 M^-1 s^-1.
What rough relationship can be infer between temperature and rate of reaction?
reaction rate doubles with every 10 K temperature change
Is the rate of a chemical reaction dependent of temperature?
In general, as temperature rises, so does reaction rate. This is because the rate of reaction is dependent on the collision of the reacting molecules or atoms. As temperature rises, molecules or atoms respond with increased motion, increasing the collision rate, thus increasing the reaction rate.
