What is the rate law for the following reaction A plus 2B creates C plus D 1 rate kAB2 2 rate kA2B 3 rate kA2 B2 4 rate kAB?

Answer 1

A + 2 B ==>C + D
rate = k[A][B]^2 if this is an elementary step. If not, you cannot determine rate equation.
So, #1 would be the best answer, i.e. rate = kAB2 but the square only applies to B and not to A, so it isn't really written correctly.

Answer 2

The rate law for the reaction A + 2B → C + D is: Rate = k[A][B]2, where k is the rate constant, [A] represents the concentration of A, and [B] represents the concentration of B. This rate law indicates that the rate of the reaction is directly proportional to the concentration of A and the square of the concentration of B.