NaHSO3 + KIO3 => I2 + NaI + K2SO4 + H2O
The reaction between osmium tetroxide (OsO4) and pyridine-NaHSO3 in the presence of water involves the formation of a complex between OsO4 and pyridine-NaHSO3, which is stabilized by water molecules. This complexation reaction helps in the reduction of osmium tetroxide to osmium dioxide, resulting in the formation of a stable product.
The chemical reaction between acetic acid (CH3COOH) and sodium sulfite (Na2SO3) results in the formation of sodium acetate (CH3COONa), sodium bisulfite (NaHSO3), and water (H2O). The balanced chemical equation for this reaction is: 2CH3COOH + Na2SO3 → 2CH3COONa + NaHSO3 + H2O. This reaction is a double displacement reaction where the cations and anions of the reactants switch places to form the products.
Equation: NaHSO3 + H2CrO4 ----> Na2CrO4 + H2O + SO2 Further reaction in Sodium hydrogen sulfite, needs Acidic condition: Na2CrO4 + NaHSO3 + H+ ----> Na2SO4 + Cr2(SO4)3 + H2O
The product of reacting E-2-Pentene with OsO4/pyridine followed by aqueous NaHSO3 is 2,3-Epoxy-5-pentanol. This reaction proceeds through syn-dihydroxylation of the alkene followed by epoxide ring formation via reaction with NaHSO3.
The reaction of an aldehyde with sodium hydrogen sulfite (NaHSO3) typically results in the formation of a bisulfite addition product. The general formula for this reaction can be represented as follows: RCHO + NaHSO3 → RCH(OH)SO3Na
The reaction between osmium tetroxide (OsO4) and pyridine-NaHSO3 in the presence of water involves the formation of a complex between OsO4 and pyridine-NaHSO3, which is stabilized by water molecules. This complexation reaction helps in the reduction of osmium tetroxide to osmium dioxide, resulting in the formation of a stable product.
Br2 + 3NaHSO3 = 2NaBr + NaHSO4 + H2O + 2SO2
The chemical reaction between acetic acid (CH3COOH) and sodium sulfite (Na2SO3) results in the formation of sodium acetate (CH3COONa), sodium bisulfite (NaHSO3), and water (H2O). The balanced chemical equation for this reaction is: 2CH3COOH + Na2SO3 → 2CH3COONa + NaHSO3 + H2O. This reaction is a double displacement reaction where the cations and anions of the reactants switch places to form the products.
Equation: NaHSO3 + H2CrO4 ----> Na2CrO4 + H2O + SO2 Further reaction in Sodium hydrogen sulfite, needs Acidic condition: Na2CrO4 + NaHSO3 + H+ ----> Na2SO4 + Cr2(SO4)3 + H2O
The product of reacting E-2-Pentene with OsO4/pyridine followed by aqueous NaHSO3 is 2,3-Epoxy-5-pentanol. This reaction proceeds through syn-dihydroxylation of the alkene followed by epoxide ring formation via reaction with NaHSO3.
KIO3 name is Potassium Iodate
The reaction of an aldehyde with sodium hydrogen sulfite (NaHSO3) typically results in the formation of a bisulfite addition product. The general formula for this reaction can be represented as follows: RCHO + NaHSO3 → RCH(OH)SO3Na
I have to laugh at you for this question. The chemical formula for KIO3 is KIO3. It's called Potassium Iodate.
The products of the reaction between KIO3 and Na2S2O5 in the iodine clock reaction are I2, NaIO3, Na2SO4, and H2O. The reaction involves the oxidation of S2O32- by I3- to produce I2, resulting in the color change characteristic of the iodine clock reaction.
The compound with the formula KIO3 is called potassium iodate.
The balanced equation for the reaction between amidosulfuric acid (NH2SO3H) and sodium hydroxide (NaOH) is: NH2SO3H + NaOH → NaHSO3 + H2O
Formula: KIO3