Please mention the reaction.
6,26 g CuO are obtained.
Copper(II) Oxide: CuO reaction with Nitric Acid: CuO + 2 HNO3 => Cu(NO3)2 + H2O Copper(I) Oxide: Cu2O reaction with Ntric Acid: Cu2O + 2HNO3 => CuNO3 + H2O
1 mole CuO = 79.5454g CuO 3.2g CuO x 1mol CuO/79.5454g CuO = 0.040 mole CuO
CuO + H2SO4 --> CuSO4 + H2O
The chemical decomposition is:CuSO4------ CuO + SO3
no reaction
No.
6,26 g CuO are obtained.
The reaction is;CuSO4 = CuO + SO3
Copper(II) Oxide: CuO reaction with Nitric Acid: CuO + 2 HNO3 => Cu(NO3)2 + H2O Copper(I) Oxide: Cu2O reaction with Ntric Acid: Cu2O + 2HNO3 => CuNO3 + H2O
1 mole CuO = 79.5454g CuO 3.2g CuO x 1mol CuO/79.5454g CuO = 0.040 mole CuO
The chemical decomposition is:CuSO4------ CuO + SO3
CuO + CH3OH --> HCHO + Cu + H2O
CuO + H2SO4 --> CuSO4 + H2O
The chemical formula for copper (ii) oxide is CuO The chemical formula for Sulphuric acid is H2SO4. So a chemical reaction between them would look like this: CuO + H2SO4 -> CuSO4 + H2O
11 g hydrogen are needed.
The thermal decomposition in this case is: CuCO3 -------------CuO + CO2