Both sodium (Na) and cesium (Cs) are alkali metals in Group 1 of the Periodic Table.
They both have one valence electron in the outermost shell.
However, between the two, cesium has 3 more energy levels than sodium (sodium is in row 3, cesium is in row 6).
Se and Te will have the same valence-shell electron configuration as they are both in the same group (group 16) and have 6 valence electrons. Sr and Cs will have different valence-shell electron configurations as Sr is in group 2 with 2 valence electrons and Cs is in group 1 with 1 valence electron. N and O will have different valence-shell electron configurations as N has 5 valence electrons while O has 6. H and He will have different valence-shell electron configurations as H has 1 valence electron and He has 2.
Caesium (Cs) has 55 electrons, and it will need to lose 1 electron to achieve a noble gas electron configuration. This is because Cs is in Group 1 of the periodic table, so losing 1 electron will leave it with the same electron configuration as the noble gas element in the previous period (Xenon).
The condensed version (which you want to use for cesium!) is [Xe]6s1 It means cesium has all the electrons in the same places that xenon has, plus one valence electron way out in the 6th level.
Cesium loses just one electron to form Cs+
The symbol for the cesium ion is Cs+. It represents cesium in its +1 oxidation state, meaning it has lost one electron to achieve a stable electron configuration.
Se and Te will have the same valence-shell electron configuration as they are both in the same group (group 16) and have 6 valence electrons. Sr and Cs will have different valence-shell electron configurations as Sr is in group 2 with 2 valence electrons and Cs is in group 1 with 1 valence electron. N and O will have different valence-shell electron configurations as N has 5 valence electrons while O has 6. H and He will have different valence-shell electron configurations as H has 1 valence electron and He has 2.
Cs does not have a nobel gas electron configuration, as it contains one valence electron in its outermost s orbital. Be3+ also does have a nobel gas electron configuration, as this occurs when Be has a 2+ charge (the typical Be ion is Be2+).
Caesium (Cs) has 55 electrons, and it will need to lose 1 electron to achieve a noble gas electron configuration. This is because Cs is in Group 1 of the periodic table, so losing 1 electron will leave it with the same electron configuration as the noble gas element in the previous period (Xenon).
The condensed version (which you want to use for cesium!) is [Xe]6s1 It means cesium has all the electrons in the same places that xenon has, plus one valence electron way out in the 6th level.
The electron configuration of caesium is: [Xe]6s1.
Cesium loses just one electron to form Cs+
Cs typically has a +1 charge, meaning it loses one electron to achieve a full outer shell configuration.
The symbol for the cesium ion is Cs+. It represents cesium in its +1 oxidation state, meaning it has lost one electron to achieve a stable electron configuration.
Cesium (Cs) has one unpaired electron in its outermost shell. It has the electron configuration of [Xe] 6s¹, meaning it has a single electron in the 6s orbital, which is not paired with any other electron. Therefore, cesium has one unpaired electron.
Cesium (Cs) is the alkali metal that requires 4 electron shells as it has the electron configuration [Xe] 6s1.
Be3+ has only 2 valence electron and not 8.
Long-hand version: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^1 Short-hand version: [Xe] 6s^1 Note: The "^" symbol means the the following number is in the form of a superscript.