Indefinite, if the containers were tightly sealed.
When you add black copper oxide to sulfuric acid, the solution turns blue because copper sulfate was formed and it is a colored compound.
Copper sulfate and water :)
It will darken the copper (II) sulfate solution.
a copper sulfate solution it becomes copper (II) sulfate pentahydrate
Sulfuric acid plus copper (II) nitrate yields nitric acid plus copper (II) sulfate. Sulfuric acid plus copper (I) nitrate yields nitrous acid plus copper (I) sulfate.
When you add black copper oxide to sulfuric acid, the solution turns blue because copper sulfate was formed and it is a colored compound.
When dilute sulfuric acid reacts with copper(II) carbonate, blue copper(II) sulfate solution is produced.
Copper sulfate and water :)
The pH of a copper sulfate solution depends on its concentration. Typically, a 1% solution of copper sulfate has a pH of around 3-4, making it acidic.
It will darken the copper (II) sulfate solution.
Heating the saturated solution of Copper sulfate will not form the hydrated copper sulfate crystals because only after cooling down the saturated solution of copper sulfate then only the crystals of the hydrated copper sulfate can be formed
CuSO4 Synonyms: Copper (II) sulfate (1:1); copper monosulfate; sulfuric acid copper (2+) salt (1:1); blue copper; anhydrous copper sulfate
a copper sulfate solution it becomes copper (II) sulfate pentahydrate
Sulfuric acid plus copper (II) nitrate yields nitric acid plus copper (II) sulfate. Sulfuric acid plus copper (I) nitrate yields nitrous acid plus copper (I) sulfate.
Copper can be obtained from copper sulfate solution by electroplating it onto an electrode or by adding a metal higher in the electromotive series than copper, such as iron, to the solution. The more active metal will dissolve by displacing copper in metallic form from the copper sulfate.
Any thing ending in sulfate e.g. calcium sulfate, copper sulfate
You will have to assume that the 2 % is a volume fraction, then the volume of copper sulfate in the solution would be 11.5 milliliter(575 ml*(0.02). If it were a weight fraction, then you would have to have more information on the solution density.