-51.88 kJ/g
The enthalpy of combustion is determined by calorimetry.
The standard enthalpy of combustion for methane is -890 kJ/mol.
-1368 kJ mol-1
The correct dimensional formula of latent heat is MoL2T2.
Enthalpy of combusion is energy change when reacting with oxygen. Enthalpy of formation is energy change when forming a compound. But some enthalpies can be equal.ex-Combusion of H2 and formation of H2O is equal
i at first wrote out the enthalpies of combustion for hydrogen ethene and ethane and then manipulated the equations , ultimately my answer ended up being -137 but when i tried to find out the enthalpy on google it just came up this quiestion did you find out what the answer was!?
Combustion.
The enthalpy of combustion is determined by calorimetry.
The standard enthalpy of combustion for methane is -890 kJ/mol.
-1368 kJ mol-1
The correct dimensional formula of latent heat is MoL2T2.
Enthalpy of combusion is energy change when reacting with oxygen. Enthalpy of formation is energy change when forming a compound. But some enthalpies can be equal.ex-Combusion of H2 and formation of H2O is equal
Ethane does not have any molecule of carbon dioxide. However when ethane undergoes combustion then two molecules of carbon dioxide are formed (as ethane contains two carbon atoms).
The enthalpy associated with pentane is roughly 1 to 1 when combustion in a vacuum chamber, if you combustion it outside you will have a greater rate of loss from the pentane.
Yes there are. These gases are hydrogen,methane,ethane,propane,butane,pentane. Hope this helped! ;)
You're gonna need an enthalpy change of formation table.
You think probable to molar heat, expressed in J/mol.