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If proton and an electron have the same speed which has the longer de Broglie wavelength?
It is electron since wavelength = h/(mv), and since proton's mass > electron's mass, electron's wavelength is longer.
How do you calculate the speed of an electron using the de Broglie wavelength?
To find this answer you will have to go through a series of formulas. The first formula you will need to use is the kinetic energy formula (K.E.=1/2mv^2). The mass of an electron is found to be 9.11 x 10^-31. You then divide the mass by two (or multiply by 0.5) and get 4.555 x 10^-31, you will then have to multiply it by your velocity squared, and get your energy in joules. With that energy, you divide by planks constant (6.6 x 10^-34) which eaves you with your frequency. With that very frequency you get the speed of light in air (3 x 10^8) and divide by your frequency which will give you the wavelength needed in meters
What is the speed of an electron in a vacuum?
The speed of an electron in a vacuum is approximately 2.2 million meters per second.
What is the speed of an electron in motion?
The speed of an electron in motion can vary, but typically ranges from about 1 to 10 of the speed of light, which is approximately 186,282 miles per second.
What is the relationship between wavelength and mass?
Wavelength lambda and frequency f are connected by the speed c of the medium. c can be air = 343 m/s at 20 degrees celsius or water at 0 dgrees = 1450 m/s. c can be light waves or electromagnetic waves = 299 792 458 m/s. The formulas are: c = lambda x f f = c / lambda lambda = c / f
If proton and an electron have the same speed which has the longer de Broglie wavelength?
It is electron since wavelength = h/(mv), and since proton's mass > electron's mass, electron's wavelength is longer.
What is de broglie's wavelength of electron in meters travelling at half a speed of light?
4.2*10-11
What is the De Broglie wavelength of an electron that strikes the back of the face of a TV screen at 19 the speed of light?
Assuming you mean that the velocity is 1/9th the speed of light then you need to use the de Broglie equation for the wavelength of a particle, which says that the wavelength is equal to Planck's constant divided by the momentum. Thus, λ = h / p = h / (m*v) = h/(m*1/9*c) = 9*h/(m*c) where λ=wavelength, h=Planck's constant, p=momentum, m=mass of the electron, v=velocity, and c=speed of light this gives λ = 9 * 6.626*10^-34 / (9.109*10^-31 * 3.00*10^8) = 2.18*10^-11 meters
An electron starting from rest accelerates through a potential difference of 388 V What is the final de Broglie wavelength of the electron assuming that its final speed is much less than the spee?
To find the final de Broglie wavelength, you can use the equation λ = h/p, where λ is the wavelength, h is Planck's constant, and p is the momentum of the electron. The momentum can be calculated as p = √(2mE), where m is the mass of the electron and E is the kinetic energy acquired from the potential difference. Find the final speed of the electron using the equation v = √(2eV/m), where e is the elementary charge. Finally, use the speed to calculate the final momentum and plug it into the de Broglie wavelength formula.
How do you calculate the speed of an electron using the de Broglie wavelength?
To find this answer you will have to go through a series of formulas. The first formula you will need to use is the kinetic energy formula (K.E.=1/2mv^2). The mass of an electron is found to be 9.11 x 10^-31. You then divide the mass by two (or multiply by 0.5) and get 4.555 x 10^-31, you will then have to multiply it by your velocity squared, and get your energy in joules. With that energy, you divide by planks constant (6.6 x 10^-34) which eaves you with your frequency. With that very frequency you get the speed of light in air (3 x 10^8) and divide by your frequency which will give you the wavelength needed in meters
Determine wavelength for electron having velocity 15.0 the speed of light?
Speed of electron as compared to speed of light is: n = 15% c = 299792458 [m/s] v = c*n/100 = 4.5 *10^7 [m/s] So corresponding wavelength as given by the de Broglie equation: h - Planck's constant, m0 - the mass of the electron at zero velocity; lambda = h/p = h/(v*m0) = 6.62606876*10^-34/(4.5 *10^7*9.10938188*10^-31) = 1.61642*10^-11 [m] = 0.16 [angstroms]
How is an electron's wavelength related to its speed and mass?
The wavelength of an electron is inversely proportional to its speed and directly proportional to its mass. This means that as the speed of an electron increases, its wavelength decreases, and as the mass of an electron increases, its wavelength also increases.
What A typical wavelength for X-radiation is 0.1nm so Calculate the speed of an electron which would have the same wavelength?
To find the speed of an electron with a wavelength of 0.1nm, you can use the de Broglie wavelength formula: λ = h / mv, where λ = wavelength, h = Planck's constant, m = mass of electron, and v = speed of electron. Rearranging the formula to solve for v, we get v = h / (mλ). Plugging in the values (h = 6.63 x 10^-34 J·s, m = 9.11 x 10^-31 kg, and λ = 0.1 x 10^-9 m), you can calculate the speed.
What is the characteristic wavelength of the electron when an electron is accelerated through a particular potential field if it attains a speed of 9.38x10 to the power of 6 ms?
The characteristic wavelength of an electron accelerated through a potential field can be calculated using the de Broglie wavelength formula: λ = h / p, where h is the Planck constant and p is the momentum of the electron. Given the speed of the electron, momentum can be calculated as p = m*v, where m is the mass of the electron. Once the momentum is determined, the wavelength can be calculated.
Does the de broglie wavelength of a photon become longer or shorter as its velocity increases?
The de Broglie wavelength of a photon remains constant as its velocity increases because a photon always travels at the speed of light in a vacuum. The wavelength of light is determined by its frequency according to the equation λ = c / f.
What is de-Broglie wavelength of an atom at absolute temperature T K?
The de Broglie wavelength of an atom at absolute temperature T K can be calculated using the formula λ = h / (mv), where h is Planck's constant, m is the mass of the atom, and v is the velocity of the atom. At higher temperatures, the velocity of atoms increases, leading to a shorter de Broglie wavelength.
Why is de broglie wavelength associated with macroscopic objects is not observed in daily life?
The de Broglie wavelength for macroscopic objects is extremely tiny due to their large mass and momentum, making it impractical to observe in daily life. Additionally, interactions with the environment cause decoherence, effectively destroying any quantum effects on a macroscopic scale.
