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Using the Ideal Gas Law pV=nRT, I can solve for T by isolating for it giving me T=pV/nR. n=0.57 mol, p=1.5 atm=151.875 kPa, R= gas constant= 8.314 kPaL/molK, and V=11.4 L. Calculating for T, I get an answer of 365.4... K. Changing that into Celsius which is Kelvin-273.15 and I get 92.197...°C. Round it to two significant digits and I get 92°C.

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Q: What is the temperature of 0.57mol of gas at a pressure of 1.5atm and a volume of 11.4L?
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