Iodine (symbol I) has atomic number 53, which means that it has 53 protons in the nucleus (by definition). Since an atom is neutral overall, and the charge on an electron is equal and opposite to that of a proton, the atom has 53 electrons.
Being a group VII element (also known as a halogen), it gains one electron to fill its outer shell when it forms an ion (the I- ion). This gives it a total of 54 electrons.
Iodine is a non metal element. There are 53 electrons in a single atom. There are 7 valence electrons. The iodide ion I- has 54 electrons.
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The element with the electron configuration Kr 5s2 4d10 5p5 is iodine, which has 53 electrons in total. The electron configuration indicates that iodine has 7 valence electrons in its outermost shell, which is in the 5p subshell.
An iodine ion typically has 53 electrons. The number of electrons in an ion is determined by its atomic number (in this case 53 for iodine) and its charge. Iodine commonly forms an anion with a charge of -1, meaning it gains one electron to achieve a stable electron configuration.
The oxidation number of lead (Pb) in PbI2 is +2. Iodine (I) typically has an oxidation number of -1 in compounds. Since there are two iodine atoms in PbI2, the total negative charge contributed by iodine is -2. This balances with the +2 charge of lead to make PbI2 neutral.
Iodine is a non metal element. There are 53 electrons in a single atom. There are 7 valence electrons. The iodide ion I- has 54 electrons.
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No, iodine has 5 electron shells. It has a total of 53 electrons and its electron configuration is [Kr] 5s2 4d10 5p5, indicating that it has 4 electron shells.
The element with the electron configuration Kr 5s2 4d10 5p5 is iodine, which has 53 electrons in total. The electron configuration indicates that iodine has 7 valence electrons in its outermost shell, which is in the 5p subshell.
I believe the answer your looking for in an Ion.An ion is an atom or molecule in which the total number of electrons is not equal to the total number of protons, giving it a net positive or negative electrical charge.
An iodine ion typically has 53 electrons. The number of electrons in an ion is determined by its atomic number (in this case 53 for iodine) and its charge. Iodine commonly forms an anion with a charge of -1, meaning it gains one electron to achieve a stable electron configuration.
The oxidation number of lead (Pb) in PbI2 is +2. Iodine (I) typically has an oxidation number of -1 in compounds. Since there are two iodine atoms in PbI2, the total negative charge contributed by iodine is -2. This balances with the +2 charge of lead to make PbI2 neutral.
The total electron number for phosphorus is 15 because phosphorus has 15 electrons.
The electron configuration of iodine (I), which has an atomic number of 53, is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁵. This configuration indicates that iodine has a total of 53 electrons, filling the respective energy levels and subshells according to the Aufbau principle. The presence of five electrons in the 4p subshell is characteristic of its reactivity as a halogen.
The atomic radius depends on the the number of electron shells, total negative charge, positive charge of the nucleus, atomic mass.
The total energy of an atom with a negative nucleus and positive electron will be negative, given that the electron is bound to the nucleus through electrostatic attraction. This negative energy results from the potential energy associated with the attraction between the oppositely charged particles.
The atomic number of iodine is 53. So there will be 53 protons in the nucleus. For iodine atom to be neutral there will 53 electrons in total.