AgNO3(aq) + KCl(aq) = AgCl(s) + KNO3(aq)
This is the classic taste for halogens. In thisd case AgCl precipiates down as a white solid.
The total ionic equation for NaCl + AgNO3 is: Na⁺ + Cl⁻ + Ag⁺ + NO₃⁻ → AgCl + Na⁺ + NO₃⁻
CuCl2(aq) + 2AgNO3(aq) = Cu(NO3)2(aq) + 2AgCl(s)
3 AgNO3 + Na3 PO4-->Ag3 PO4 + 3 NaNO3 You need three silver nitrate molecules:one sodium phosphat molecule to complete the reaction. Just swap the ions.
The symbol equation for the reaction between ethanoic acid and silver nitrate solution is: CH3COOH + AgNO3 -> AgCH3COO + HNO3
The net ionic equation for the given reaction is H+ (aq) + OH- (aq) → H2O (l)
The total ionic equation for NaCl + AgNO3 is: Na⁺ + Cl⁻ + Ag⁺ + NO₃⁻ → AgCl + Na⁺ + NO₃⁻
CuCl2(aq) + 2AgNO3(aq) = Cu(NO3)2(aq) + 2AgCl(s)
The chemical equation is:3 AgNO3 + FeCl3 = 3 AgCl + Fe(NO3)33 Ag + 3 NO3- + Fe3+ + 3 Cl- = 3 AgCl(s) + 3 NO3- + Fe3+
3 AgNO3 + Na3 PO4-->Ag3 PO4 + 3 NaNO3 You need three silver nitrate molecules:one sodium phosphat molecule to complete the reaction. Just swap the ions.
The word equation for silver nitrate plus sodium chloride is "silver nitrate + sodium chloride → silver chloride + sodium nitrate". The symbol equation for this reaction is "AgNO3 + NaCl → AgCl + NaNO3".
2AgNO3 + CaSO4 ------> Ag2SO4 + Ca(NO3)2
The symbol equation for the reaction between ethanoic acid and silver nitrate solution is: CH3COOH + AgNO3 -> AgCH3COO + HNO3
The net ionic equation for the given reaction is H+ (aq) + OH- (aq) → H2O (l)
The reaction between sodium bromide (NaBr) and silver nitrate (AgNO3) results in the formation of silver bromide (AgBr) and sodium nitrate (NaNO3). The balanced chemical equation for this reaction is: 2NaBr + AgNO3 → 2AgBr + 2NaNO3
The reaction of the above ionic equation will be a very complicated formula. This seems very complicated to the average person but it means a lot to scientists who study ionic reactions. Unfortunately when I try to list the formula for the resulting equation I get an error.
The balanced molecular equation is CaCl2 + Na2S -> CaS + 2NaCl. To write the ionic equation, we need to break down the reactants and products into their respective ions. This results in the ionic equation: Ca2+ + 2Cl- + 2Na+ + S2- -> CaS + 2Na+ + 2Cl-. Cross out spectator ions that appear on both sides of the equation to obtain the net ionic equation: Ca2+ + S2- -> CaS.
The balanced equation is: 2AgNO3 + 2NaBr → 2NaNO3 + 2AgBr.