it is a non-polar covalent bond.
therefore, the force between the molecules is known as the London dispersion force.
The intermolecular force present in HBr is dipole-dipole interaction. This occurs due to the electronegativity difference between hydrogen and bromine, causing a permanent dipole moment in the molecule that results in intermolecular attractions between neighboring HBr molecules.
Among the given molecules, bromine (Br2) has the highest vapor pressure due to its relatively low boiling point and weak intermolecular forces between its molecules. Water (H2O) has a lower vapor pressure compared to bromine because of its stronger hydrogen bonding. Nitrogen trichloride (NCl3) has the lowest vapor pressure since it is a polar molecule with stronger intermolecular forces compared to the other two molecules.
NaCl is ionically bonded with stong electrostatic attractions whereas Cl2 only has weak Van Der Waals' forces acting between the molecules More strength is needed to break NaCl's bonds than CL2's bonds. Therefore, NaCl is solid and Cl2 is a gas Hope this helps :)
The pairing of Br2 with polar covalent bonding is incorrect. Br2 exhibits nonpolar covalent bonding due to the similar electronegativities of the two bromine atoms causing a symmetrical distribution of electrons, resulting in a nonpolar molecule.
Br2 + 3NaHSO3 = 2NaBr + NaHSO4 + H2O + 2SO2
Br2 molecule is non polar.So intermolecular force is Vander woals.
Dipole-Dipole and covalent sigma bond forces.
The intermolecular force present in HBr is dipole-dipole interaction. This occurs due to the electronegativity difference between hydrogen and bromine, causing a permanent dipole moment in the molecule that results in intermolecular attractions between neighboring HBr molecules.
No, the reaction 2K + Br2 is not balanced. To balance it, you would need to change the coefficients of the reactants and products so that the same number of each type of atom is present on both sides of the reaction arrow.
First convert the volume of the Br2 into grams by using:D=M/VSo we are given that volume=16.0 ml and density=3.12g/ml.M=D*VM=(3.12g/ml)*(16.0ml)=49.92 gThen we use #moles of a substance=#grams present/Formula weight(# of grams of Br2 in 1 mol of Br2)The Formula weight(molar mass) of Br2=2*(79.9 g/mol)=159.80 g/mol Br2#moles of Br2=49.92g/159.80g/mol Br2=.312 moles of Br2 present.
Among the given molecules, bromine (Br2) has the highest vapor pressure due to its relatively low boiling point and weak intermolecular forces between its molecules. Water (H2O) has a lower vapor pressure compared to bromine because of its stronger hydrogen bonding. Nitrogen trichloride (NCl3) has the lowest vapor pressure since it is a polar molecule with stronger intermolecular forces compared to the other two molecules.
NaCl is ionically bonded with stong electrostatic attractions whereas Cl2 only has weak Van Der Waals' forces acting between the molecules More strength is needed to break NaCl's bonds than CL2's bonds. Therefore, NaCl is solid and Cl2 is a gas Hope this helps :)
The pairing of Br2 with polar covalent bonding is incorrect. Br2 exhibits nonpolar covalent bonding due to the similar electronegativities of the two bromine atoms causing a symmetrical distribution of electrons, resulting in a nonpolar molecule.
Br2 + 3NaHSO3 = 2NaBr + NaHSO4 + H2O + 2SO2
44.0 grams Br2 ? 44.0 grams Br2 (1 mole Br2/159.8 grams)(6.022 X 10^23/1 mole Br2)(1 mole Br2 atoms/6.022 X 10^23) = 0.275 moles of Br2 atoms
There are two bromine atoms in Br2
The balanced equation for the reaction between zinc (Zn) and bromine (Br2) is: Zn + Br2 -> ZnBr2.