Silicon tetrahydride is a tetrahedral molecule. The silicon atom is directly bonded with four hydrogen atoms where the hydrogen atoms lie at the corners of the tetrahedron. According to the VSEPR theory, it has a bond angle of 109.5 degrees.
The bond angles in BrF5 are approximately 90 degrees.
If it is non polar, the bond angles are as follows:I-P-I bond angles: 120ºBr-P-Br bond angles: 180ºI-P-Br bond angles: 90º
The bond angle in TeO2 is approximately 104 degrees. This value is influenced by the repulsion between the lone pairs of electrons on the Te atom and the bonding electrons.
The bond angles in HClO3 are approximately 109.5 degrees.
The bond angles in HNO2 are approximately 120 degrees.
The bond angles in BrF5 are approximately 90 degrees.
109.5
180
The bond angles in IF4^- (iodine tetrafluoride) are approximately 90 degrees.
The predicted structure for SiH4 based on VSEPR theory is tetrahedral. This is because silicon (Si) has four valence electrons and forms four single bonds with hydrogen atoms, resulting in a tetrahedral geometry where the bond angles are approximately 109.5 degrees.
If it is non polar, the bond angles are as follows:I-P-I bond angles: 120ºBr-P-Br bond angles: 180ºI-P-Br bond angles: 90º
The value of the bond angle in XeF2 is 180 degrees.
The bond angle in TeO2 is approximately 104 degrees. This value is influenced by the repulsion between the lone pairs of electrons on the Te atom and the bonding electrons.
The bond angles are 120 degrees
The bond angles of CO2 are 180 degrees.
90 and 180 are the approximate bond angles.
The bond angles in HClO3 are approximately 109.5 degrees.