The property that relates mass to volume is density, so we must know the density of copper to solve this. I looked it up and found it to be 8.96 grams per cubic cm. Since density is mass divided by volume (D=m/V), and we want the volume, we multiply both sides by V: DV=mV/V. V divided by V is 1, so DV=m. To get V alone, divide both sides by D: DV/D=m/D. Now the D/D cancels out, and: V=m/D. The mass is 10 g, the density 8.96g/cm3, and 10g/(8.96g/cm3) is 1.1 cm3.
Since the specific gravity of copper is 8.95, the volume of 126 grams of copper is 14.08 cubic centimeters (126/8.95 cm3).
The density of copper is about 8.96 grams per cubic centimeter. Therefore, the density of a material with a mass of 1800 grams and a volume of 200 cm3 would be approximately 9 g/cm3, given that the material is copper.
To calculate the mass of 19 atoms of copper in grams, you need to determine the molar mass of copper. The molar mass of copper is approximately 63.55 grams per mole. Then, you can use Avogadro's number (6.022 x 10^23 atoms per mole) to convert atoms to grams. So, the mass of 19 atoms of copper would be 19*(63.55/6.022e23) grams.
What is the weight in grams of 3.36 × 1023 molecules of copper sulfate (CuSO4)?
To calculate the number of copper atoms in the statue, you first need to find the moles of copper present in 133 kg using its molar mass. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of copper to atoms.
89.2g
You need to multiply the volume, by the density of copper.
The density of copper is 8.94 grams per cm3. The mass will depend on the volume of the "lump" of copper.
8.9 grams/mL x 396 mL = 3524.4 grams, or about 3.5 kg
10 grams of copper can kill you. But copper sulphate won't kill you. So don't freak out!
Density is an intensive property because it does not depend on the amount of matter present. If you have 2 grams of copper and 2000 grams of copper, they are going to have the same density. This cannot be said for extensive properties such as volume: 2 grams of copper will not have the same volume as 2000 grams of copper.See related questions below for more information.
Density is an intensive property because it does not depend on the amount of matter present. If you have 2 grams of copper and 2000 grams of copper, they are going to have the same density. This cannot be said for extensive properties such as volume: 2 grams of copper will not have the same volume as 2000 grams of copper.See related questions below for more information.
For the same size truckload, the dimes are much more valuable. For the same weight or volume, there is more value in the smaller 10-cent coin than in the larger, heavier 5-cent piece.For comparison:Nickel - 5.0 grams, volume 689 mm3Dime - 2.268 grams, volume 340 mm3*Based on the metal content, a nickel is more valuable because it contains 75% copper, about 3.75 grams. The dime is 91.67% copper, about 2.08 grams. But you would still have more copper per volume or weight taking the dimes.
There are 453.592 grams in a pound, so 10 pounds would be 4535.92 grams. The density of copper, the main component of pennies, is 8.96 grams per cubic centimeter. A penny has a volume of 0.36 cubic centimeters, so 4535.92 grams of pennies would have a volume of 5050.89 cubic centimeters. With 2.5 grams per penny, there would be approximately 2023 pennies in 10 pounds, which would total $20.23.
Since the specific gravity of copper is 8.95, the volume of 126 grams of copper is 14.08 cubic centimeters (126/8.95 cm3).
To find the mass of a piece of copper, you can use the formula: mass = volume × density. Given that the volume is 5.00 cubic centimeters and the density of copper is 8.96 grams per cubic centimeter, the mass would be 5.00 cm³ × 8.96 g/cm³ = 44.80 grams. Thus, the mass of the copper piece is 44.80 grams.
The volume of 10 grams of sugar depends on the density of the sugar. The volume can be calculated by dividing the mass by the density of the sugar. For example, if the density of sugar is 1.59 g/cm3, then the volume of 10 grams of sugar would be approximately 6.29 cm3.