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When copper is heated in air, it undergoes oxidation to form copper(II) oxide. The chemical equation for this process is: 2Cu(s) + O2(g) → 2CuO(s)
When a copper wire is heated with a Bunsen burner, it undergoes oxidation as it reacts with oxygen in the air, forming copper(II) oxide (CuO) on its surface. The balanced chemical equation for this reaction is: 2Cu + O2 -> 2CuO.
2Cu(NO3)2 = 2CuO +4NO2 +O2
Since there are two valence states for copper, Cu+ and Cu2+, there are two compounds formed from copper and oxygen:Copper (I) Oxide = Cu2O (equation: 4Cu + O2 --> 2Cu2O)Copper (II) Oxide = CuO (equation: 2Cu + O2 --> 2CuO)
The balanced equation for the corrosion of copper is: 2Cu(s) + O2(g) + H2O(l) + 2e- -> 2Cu2+(aq) + 2OH-(aq)
When copper is heated in air, it reacts with oxygen to form copper oxide. The equation for this reaction is: 2Cu(s) + O2(g) -> 2CuO(s)
2Cu (s) + O2 (g) -----------------> 2CuO (s)
2Cu+O2 ---> 2CUO
Oxidation
2Cu(NO3)2(s)+heat------->2CuO(s)+4NO2(g)+O2(g)
The final answer would be 2Cu O2---> 2CuO
2Cu + O2 yields 2CuO
2Cu(s) + O2(g) --> 2CuO(s)
When copper is heated in air, it undergoes oxidation to form copper(II) oxide. The chemical equation for this process is: 2Cu(s) + O2(g) → 2CuO(s)
2Cu + O2 ==> 2CuO product is copper(II) oxide4Cu + O2 ==> 2Cu2O product is copper(I) oxide
When a copper wire is heated with a Bunsen burner, it undergoes oxidation as it reacts with oxygen in the air, forming copper(II) oxide (CuO) on its surface. The balanced chemical equation for this reaction is: 2Cu + O2 -> 2CuO.
2Cu(NO3)2 = 2CuO +4NO2 +O2