I dont no help
combination
2Cu(NO3)2 = 2CuO +4NO2 +O2
Exothermic, combustion
Cu2 should be '2Cu' ( two uncombined atoms of copper.) O2- should be 'O2; ( 2 combined atoms of oxygen). When heated 2Cu(s) + O2(g) = 2CuO(s) CuO is copper oxide and appears as a black solid.
Copper and oxygen react to form copper (I) oxide, Cu2O, and copper (II) oxide, CuO. 4Cu + O2 --> 2Cu2O 2Cu + O2 --> 2CuO
2Cu + O2 -> 2CuO Now you have an ionic bond because the oxygen has taken two electrons from copper into it's valance shell. Thus, copper is oxidized; loses electrons.
2Cu(s)+O2(g) → 2CuO(s)
2Cu (s) + O2 (g) -----------------> 2CuO (s)
2Cu+O2 ---> 2CUO
Oxidation
The final answer would be 2Cu O2---> 2CuO
2Cu + O2 yields 2CuO
2Cu(NO3)2(s)+heat------->2CuO(s)+4NO2(g)+O2(g)
2Cu(s) + O2(g) --> 2CuO(s)
2Cu(NO3)2 = 2CuO +4NO2 +O2
2Cu + O2 ==> 2CuO product is copper(II) oxide4Cu + O2 ==> 2Cu2O product is copper(I) oxide
Exothermic, combustion
Cu2 should be '2Cu' ( two uncombined atoms of copper.) O2- should be 'O2; ( 2 combined atoms of oxygen). When heated 2Cu(s) + O2(g) = 2CuO(s) CuO is copper oxide and appears as a black solid.