The law is:
Needed electricity in coulombs = Faraday constant (96500 C) x number of moles
So 96500 coulombs are needed.
in one electron there is a charge of 1.60217646 × 10-19 coulombs now to get your answer its going to be 1110 * 1.60217646 × 10-19 coulombs= 1.7784158706 x 10^-16
First you have to find the coulombs. Then you convert coulombs to faradays. (there are 96500 coulombs in one faraday). 1 faraday is equal to one mole electron. Then, by using a half-reaction of the anode (Cu + 2e- > CuS), you can determine there are 2 mole electrons for every mole of copper.
Robert Millikan
3 Coulombs
The deposited amount should be.....= Equivalet mass/F grams. (F= 96500 coulombs).
newtons gravitational law is similar to that of coulomb's law...
Limitations of coulombs law
Germigny-sous-Coulombs's population is 194.
The population of Coulombs-en-Valois is 606.
1.6x10^-19 coulombs/electron x 12.5x10^18 electrons = 20 coulombs
The area of Germigny-sous-Coulombs is 6,530,000.0 square meters.
The area of Coulombs-en-Valois is 22.41 square kilometers.
The magnitude of the charge on a photon is 4/3 atto Coulombs, 1.33E-18 Coulombs.
Coulombs did not discover America. America was discovered by Christopher Columbus in 1492.
Current in amperes is coulombs per second, so 2 coulombs per second is 2 amperes.
in one electron there is a charge of 1.60217646 × 10-19 coulombs now to get your answer its going to be 1110 * 1.60217646 × 10-19 coulombs= 1.7784158706 x 10^-16
No