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The single oxidation of a tertiary alcohol forms?

no reaction.


What is the nutrient that forms a coating on nerves?

The class of nutrient that is necessary for production of certain hormones and that forms a coating on nerves is


What nutrient is change by bacteria into different forms?

nitrogen


How can you identify ketone in a organic unknown?

It has a C=O group attached to two R groups.


What is a passive transport protein that forms a pure through which water?

a. a sodium ion b. anaiotensinogen c. ketone bodies d. aquaporin


What is the name Ketone with 6 carbons?

methyl ethyl ketone


What is an aldosulose?

An aldosulose is another name for a ketoaldose, a monosaccharide which contains both an aldehyde and a ketone functional group in equilibrium with one or more hemiacetal forms.


Which nutrient is nescessary for production of certain hormone and that forms a coating on nerves?

fat


Why iodoform is used for functional group detection test?

Iodoform is used in the iodoform test to detect the presence of a methyl ketone functional group. When Iodoform reacts with a methyl ketone in the presence of a base and acidic conditions, it forms a yellow precipitate of iodoform, which confirms the presence of the CH3CO- group.


What classification of alcohol undergoes oxidation to yield a ketone?

A secondary alcohol undergoes oxidation to yield a ketone; a primary alcohol forms an aldehyde instead, and a tertiary alcohol usually does not form either a ketone or an alcohol, because the carbon having the OH group in a tertiary alcohol already has three bonds to other carbon atoms and therefore cannot form a double bond to oxygen without more extensive breaking of other bonds in the tertiary alcohol.


The class of nutrient that is necessary for production of certain hormones and that forms a coating on nerves is?

fat


What is iodoform test do to 2 butanone?

The iodoform test is used to detect the presence of a methyl ketone. When 2-butanone is treated with iodine and sodium hydroxide, a yellow precipitate of iodoform (CHI3) forms if 2-butanone is present. This test confirms the presence of a methyl ketone functional group in the compound.