The precipitate would be calcium carbonate, CaCO3.
Yes, the silver nitrate test is a confirmatory test for chloride ions, which react with silver ions to form a white precipitate of silver chloride. Therefore, if the silver nitrate test produced a white precipitate in all three solutions, it provides strong evidence that the residue was indeed potassium chloride.
No, reacting zinc with hydrogen chloride will yield zinc chloride and hydrogen gas. Potassium chloride can be prepared by reacting potassium with hydrogen chloride or (more safely) potassium hydroxide with hydrogen chloride.
"Potassium hydroxide hydrogen" is meaningless.
When hydrochloric acid reacts with potassium hydroxide, potassium chloride and water are produced. This is a neutralization reaction that forms a salt (potassium chloride) and water as the products.
To determine the grams of potassium chloride formed, you first need to calculate the moles of oxygen produced by the decomposition of potassium chlorate. Then, use the stoichiometry of the balanced chemical equation to convert moles of oxygen to moles of potassium chloride. Finally, from the molar mass of potassium chloride, you can calculate the grams formed.
When mercuric chloride is mixed with potassium iodide, a white precipitate of mercuric iodide is formed. This reaction is a double displacement reaction where the ions in the two compounds switch partners. Mercury(II) chloride is soluble in water, while potassium iodide is also soluble, so their reaction forms the insoluble mercuric iodide precipitate.
Potassium carbonate cannot be prepared by the Solvay process because potassium salts are highly soluble in water, making it difficult to separate potassium carbonate from the solution produced in the process. The Solvay process is specifically designed for the production of sodium carbonate, which has different solubility properties compared to potassium carbonate.
Yes, the silver nitrate test is a confirmatory test for chloride ions, which react with silver ions to form a white precipitate of silver chloride. Therefore, if the silver nitrate test produced a white precipitate in all three solutions, it provides strong evidence that the residue was indeed potassium chloride.
No, reacting zinc with hydrogen chloride will yield zinc chloride and hydrogen gas. Potassium chloride can be prepared by reacting potassium with hydrogen chloride or (more safely) potassium hydroxide with hydrogen chloride.
Since it is a double displacement and the products of the reaction would be sodium nitrate and calcium carbonate, the precipitate would be calcium carbonate. This is because this reaction is a solubility based reaction, and sodium nitrate is a soluble compound (every metal is soluble in nitrate, and sodium dissolves in almost everything too). Whereas calcium carbonate is insoluble, and therefore will remain solid and form the precipitate.
"Potassium hydroxide hydrogen" is meaningless.
BaCl2; Barium chloride.
There need to be more details provided to answer this question. If you are referring to the white precipitate that is produced in the bromination of phenol which is also known as phenylamine by adding bromine(aq) to phenol or phenylamine then the answer is 2,4,6-tribromophenol or it can be written as 2,4,6-tribromophenylamine.
When hydrochloric acid reacts with potassium hydroxide, potassium chloride and water are produced. This is a neutralization reaction that forms a salt (potassium chloride) and water as the products.
When iron sulfate and sodium carbonate are mixed, iron carbonate and sodium sulfate are produced. Iron carbonate is a solid precipitate that can be formed during the reaction, while sodium sulfate remains in solution.
This is the basic copper carbonate - Cu2(OH)2CO3.
To determine the grams of potassium chloride formed, you first need to calculate the moles of oxygen produced by the decomposition of potassium chlorate. Then, use the stoichiometry of the balanced chemical equation to convert moles of oxygen to moles of potassium chloride. Finally, from the molar mass of potassium chloride, you can calculate the grams formed.