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I believe you would have to use the formular PV=nRT for this problem.

First convert n from kg to moles, knowing that Neon is 20.1797 g/mol:

(5 kg x 1 mol) / .0201797 kg = 247 mols

Next, identify all the variables:

P = ?

V = 200-L

T = 300 K

n = 247 mols

R = 0.08206 (L*atm)/(K*mol)

Now plug the values into the formula:

PV = nRT therefore P = nRT /V

P = (247 mols)(0.08206 (L*atm)/(K*mol))(300 K) / 200-L = 30.4 atm

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9y ago
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Q: What pressure exists in a 200-L tank containing 5.0 kg of neon gas at 300 K?
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