The reaction between MgO (magnesium oxide) and NaOH (sodium hydroxide) results in the formation of magnesium hydroxide (Mg(OH)2) and sodium oxide (Na2O). This is a double displacement reaction where the magnesium ion from MgO replaces the sodium ion in NaOH, forming Mg(OH)2 and Na2O. Magnesium hydroxide is a white solid that is sparingly soluble in water, while sodium oxide is a white solid that is highly reactive with water.
The products of the reaction are sodium chloride (NaCl) and water (H2O) formed through the combination of hydrochloric acid (HCl) and sodium hydroxide (NaOH).
The chemical reaction is:Na2Cr2O7 + 2 NaOH = 2 Na2CrO4 + H2O
the products are CH3COOH + NaOH ------CH3COONa + H2O
Sodium chloride, common salt. NaOH + HCl = NaCl + H2O
The products of the reaction between hydrochloric acid and solid sodium hydroxide are water and sodium chloride (NaCl). The balanced chemical equation for this reaction is: HCl + NaOH -> NaCl + H2O.
The products of the reaction are sodium chloride (NaCl) and water (H2O) formed through the combination of hydrochloric acid (HCl) and sodium hydroxide (NaOH).
The chemical reaction is:Na2Cr2O7 + 2 NaOH = 2 Na2CrO4 + H2O
the products are CH3COOH + NaOH ------CH3COONa + H2O
Sodium chloride, common salt. NaOH + HCl = NaCl + H2O
The products of the reaction between hydrochloric acid and solid sodium hydroxide are water and sodium chloride (NaCl). The balanced chemical equation for this reaction is: HCl + NaOH -> NaCl + H2O.
First, its HCl, with a lowercase L, not HCI. The reaction is HCl + NaOH --> H2O + NaCl
The reaction between NaOH (sodium hydroxide) and KBr (potassium bromide) would result in the formation of NaBr (sodium bromide) and KOH (potassium hydroxide) as products. This is a double displacement reaction where the cations and anions switch partners.
When sodium acetate reacts with sodium hydroxide, a double displacement reaction occurs. The products of the reaction are sodium hydroxide and sodium acetate. The balanced chemical equation for this reaction is: CH3COONa + NaOH → CH3COONa + NaOH
The reaction between hydrochloric acid (HCl) and solid sodium hydroxide (NaOH) forms water (H2O) and sodium chloride (NaCl) as the products. This reaction is a neutralization reaction that produces a salt and water.
The products of the reaction between alkali metals and water are a hydroxide and hydrogen:2 Na + 2 H2O = 2 NaOH + H2
The balanced chemical equation for the reaction between HCl and NaOH is: HCl + NaOH -> NaCl + H2O Since the stoichiometry of the reaction is 1:1 for NaCl and HCl, if 1.4 moles of HCl react, then 1.4 moles of NaCl will be formed.
The reaction between dilute HCl and NaOH is a neutralization reaction, which produces water and a salt (sodium chloride) as products. In this reaction, the acid (HCl) reacts with the base (NaOH) to form water and a salt. The hydrogen ions from the acid react with the hydroxide ions from the base to form water, while the sodium and chloride ions combine to form sodium chloride.