All you need is propanoic acid. Added in an condensation reation.
The hydrolysis of ethyl propanoate with aqueous sodium hydroxide will produce propanoic acid and ethyl alcohol.
To determine the total mass of 1-pentanol that will dissolve in 110 grams of water to produce a saturated solution, you would need to know the solubility of 1-pentanol in water at a specific temperature. Once you have that information, you can calculate the total mass of 1-pentanol that will dissolve by adding the mass of the water to the mass of the 1-pentanol that can dissolve in it to form a saturated solution.
To produce ethyl propanoate from iodoethane, you would first need to react iodoethane (CH3CH2I) with sodium propanoate (CH3CH2COONa) in the presence of dry ethanol (CH3CH2OH) or other esterification catalysts. The reaction would result in the formation of ethyl propanoate (CH3CH2COOCH2CH3) along with sodium iodide (NaI) as a byproduct.
The substance that reacts chemically with another to produce heat is called a "reactant."
The molar heat of combustion of pentanol is 3329 kJ mol-1 according to http://www.creative-chemistry.org.uk/gcse/documents/Module7/N-m07-24.pdf
The hydrolysis of ethyl propanoate with aqueous sodium hydroxide will produce propanoic acid and ethyl alcohol.
To determine the total mass of 1-pentanol that will dissolve in 110 grams of water to produce a saturated solution, you would need to know the solubility of 1-pentanol in water at a specific temperature. Once you have that information, you can calculate the total mass of 1-pentanol that will dissolve by adding the mass of the water to the mass of the 1-pentanol that can dissolve in it to form a saturated solution.
To produce ethyl propanoate from iodoethane, you would first need to react iodoethane (CH3CH2I) with sodium propanoate (CH3CH2COONa) in the presence of dry ethanol (CH3CH2OH) or other esterification catalysts. The reaction would result in the formation of ethyl propanoate (CH3CH2COOCH2CH3) along with sodium iodide (NaI) as a byproduct.
To determine the limiting reactant, we need to find the moles of each reactant. Then, we calculate the amount of ammonia that can be produced from each reactant. Whichever reactant produces the least amount of ammonia is the limiting reactant. Finally, we calculate the grams of ammonia produced based on the limiting reactant.
Mercury could be a reactant or a product, depending on the reaction. Reactants react to produce products.
The substance that reacts chemically with another to produce heat is called a "reactant."
The molar heat of combustion of pentanol is 3329 kJ mol-1 according to http://www.creative-chemistry.org.uk/gcse/documents/Module7/N-m07-24.pdf
The limiting reactant is oxygen.
The limiting reactant is chlorine.
Red, green, and blue light combine to produce white light.
oxygen...got it from studyisland
produce