This is a Composition Reaction (also known as Formation Reaction).... element + element ------> compound
The reaction of sulfur trioxide (SO3) with water (H2O) produces sulfuric acid (H2SO4) according to the following equation: SO3 + H2O → H2SO4. This is an example of a hydration reaction where the SO3 molecule reacts with water to form a new compound, sulfuric acid.
The equilibrium constant for the reaction SO2(g) + NO2(g) ⇌ SO3(g) + NO(g) is given by the expression Kc = [SO3][NO]/[SO2][NO2], where square brackets denote molar concentrations. The numerical value of this equilibrium constant would depend on the specific conditions of the reaction.
The reaction between sulfuric acid (H2SO4) and sulfur trioxide (SO3) to form sulfuric acid (H2SO4) is a reversible reaction known as the sulfuric acid hydration reaction. The water (H2O) acts as a reactant in this reaction to hydrate the sulfur trioxide, forming additional sulfuric acid.
The reaction of oxalic acid (C2H2O4) with sulfuric acid (H2SO4) produces water, carbon dioxide, sulfur dioxide, and oxalate ions. This reaction is a redox reaction where oxalic acid acts as a reducing agent and sulfuric acid as an oxidizing agent.
The equation FeSO4 = Fe2O3 + SO2 + SO3 is not balanced. To balance it, one possible balanced equation could be: 2FeSO4 = Fe2O3 + 2SO2 + 2SO3.
The balanced equation for the reaction between SO3 and H2O is: SO3 + H2O → H2SO4
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
SO3 + H2O --> H2SO4 commonly called sulfuric acid.
Increasing the concentration of either SO2 or O2 would drive the reaction towards the formation of more SO3, resulting in an increase in the concentration of SO3. Increasing the temperature, however, would cause the greatest increase in the concentration of SO3 as it favors the forward reaction which produces more SO3.
1:2, does this need explaining???? 1-O2 for every 2-SO3 thus 1:2
The reaction of sulfur trioxide (SO3) with water (H2O) produces sulfuric acid (H2SO4) according to the following equation: SO3 + H2O → H2SO4. This is an example of a hydration reaction where the SO3 molecule reacts with water to form a new compound, sulfuric acid.
S8 + 12O2 = 8SO3.Since there are 8 sulfur on the left, you must have 8 on the right, so 8SO3. Now you have 24 oxygen on the right, so you need 24 on the left. Multiplying O2 by 12 balances it.
The equilibrium constant for the reaction SO2(g) + NO2(g) ⇌ SO3(g) + NO(g) is given by the expression Kc = [SO3][NO]/[SO2][NO2], where square brackets denote molar concentrations. The numerical value of this equilibrium constant would depend on the specific conditions of the reaction.
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
The reaction between sulfuric acid (H2SO4) and sulfur trioxide (SO3) to form sulfuric acid (H2SO4) is a reversible reaction known as the sulfuric acid hydration reaction. The water (H2O) acts as a reactant in this reaction to hydrate the sulfur trioxide, forming additional sulfuric acid.
The chemical reaction is:2 SO2 + O2 ↔ 2 SO3
No, there is no change in any oxidation states.